• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            隨筆 - 87  文章 - 279  trackbacks - 0
            <2025年7月>
            293012345
            6789101112
            13141516171819
            20212223242526
            272829303112
            3456789

            潛心看書研究!

            常用鏈接

            留言簿(19)

            隨筆分類(81)

            文章分類(89)

            相冊

            ACM OJ

            My friends

            搜索

            •  

            積分與排名

            • 積分 - 217919
            • 排名 - 117

            最新評論

            閱讀排行榜

            評論排行榜

            Lake Counting
            Time Limit:1000MS? Memory Limit:65536K
            Total Submit:1360 Accepted:629

            Description
            Due to recent rains, water has pooled in various places in Farmer John's field, which is represented by a rectangle of N x M (1 <= N <= 100; 1 <= M <= 100) squares. Each square contains either water ('W') or dry land ('.'). Farmer John would like to figure out how many ponds have formed in his field. A pond is a connected set of squares with water in them, where a square is considered adjacent to all eight of its neighbors.

            Given a diagram of Farmer John's field, determine how many ponds he has.

            Input
            * Line 1: Two space-separated integers: N and M

            * Lines 2..N+1: M characters per line representing one row of Farmer John's field. Each character is either 'W' or '.'. The characters do not have spaces between them.

            Output
            * Line 1: The number of ponds in Farmer John's field.

            Sample Input

            10 12
            W........WW.
            .WWW.....WWW
            ....WW...WW.
            .........WW.
            .........W..
            ..W......W..
            .W.W.....WW.
            W.W.W.....W.
            .W.W......W.
            ..W.......W.

            Sample Output

            3

            Hint
            OUTPUT DETAILS:

            There are three ponds: one in the upper left, one in the lower left,and one along the right side.

            Source
            USACO 2004 November

            #include? < iostream >
            using ? namespace ?std;

            const ? int ?MAX? = ? 102 ;
            int ?g[MAX][MAX];

            void ?travel( int ?i,? int ?j)
            {
            ????
            int ?incr[ 8 ][ 2 ]? = ? { { 0 , - 1 } ,? { 1 , - 1 } ,? { 1 , 0 } ,? { 1 , 1 } ,? { 0 , 1 } ,? { - 1 , 1 } ,? { - 1 , 0 } ,? { - 1 , - 1 } } ;
            ????
            int ?k;
            ????
            int ?tmpI,?tmpJ;
            ????
            for ?(k = 0 ;?k < 8 ;?k ++ )? {
            ????????tmpI?
            = ?i? + ?incr[k][ 0 ];
            ????????tmpJ?
            = ?j? + ?incr[k][ 1 ];
            ????????
            if ?(g[tmpI][tmpJ]? == ? 1 )? {
            ????????????g[tmpI][tmpJ]?
            = ? - 1 ;
            ????????????travel(tmpI,?tmpJ);
            ????????}

            ????}

            }


            int ?main()
            {
            ????
            int ?n,?m;
            ????
            int ?i,?j;
            ????
            int ?ans? = ? 0 ;
            ????
            char ?t;
            ????cin?
            >> ?n? >> ?m;
            ????
            for ?(i = 0 ;?i <= m + 1 ;?i ++ )? {
            ????????g[
            0 ][i]? = ? - 1 ;
            ????????g[n
            + 1 ][i]? = ? - 1 ;
            ????}

            ????
            for ?(i = 0 ;?i <= n + 1 ;?i ++ )? {
            ????????g[i][
            0 ]? = ? - 1 ;
            ????????g[i][m
            + 1 ]? = ? - 1 ;
            ????}

            ????
            for ?(i = 1 ;?i <= n;?i ++ )? {
            ????????
            for ?(j = 1 ;?j <= m;?j ++ )? {
            ????????????cin?
            >> ?t;
            ????????????
            if ?(t? == ? ' W ' )? {
            ????????????????g[i][j]?
            = ? 1 ;
            ????????????}
            ? else ? {
            ????????????????g[i][j]?
            = ? 0 ;
            ????????????}

            ????????}

            ????}

            ????
            for ?(i = 1 ;?i <= n;?i ++ )? {
            ????????
            for ?(j = 1 ;?j <= m;?j ++ )? {
            ????????????
            if ?(g[i][j]? == ? 1 )? {
            ????????????????ans
            ++ ;
            ????????????????g[i][j]?
            = ? - 1 ;
            ????????????????travel(i,?j);
            ????????????}

            ????????}

            ????}

            ????cout?
            << ?ans? << ?endl;
            ????
            return ? 0 ;
            }
            感受遞歸的神奇!
            posted on 2006-05-01 18:48 閱讀(712) 評論(0)  編輯 收藏 引用 所屬分類: ACM題目
            久久亚洲中文字幕精品有坂深雪| 久久精品国产99久久久香蕉| 人妻系列无码专区久久五月天| 一级做a爰片久久毛片16| 国产三级观看久久| 伊人久久大香线蕉AV一区二区| 久久只这里是精品66| 男女久久久国产一区二区三区| 亚洲人成网站999久久久综合| 久久久久久久亚洲精品| 精品久久久久久无码中文字幕| 亚洲精品高清一二区久久 | 国产成人久久777777| 色综合久久综精品| 国内精品久久久久久久久电影网| 99久久精品午夜一区二区| 久久天天躁狠狠躁夜夜不卡| 国产精品99精品久久免费| 国产精品99久久精品| 午夜精品久久久久久99热| 国产免费福利体检区久久| 久久亚洲色一区二区三区| 麻豆久久| 精品久久人妻av中文字幕| 色综合久久综合网观看| 亚洲欧美另类日本久久国产真实乱对白 | 久久伊人精品青青草原高清| 欧美激情精品久久久久久| 久久久久久久久久久久久久| 国产高清美女一级a毛片久久w| 国产精品日韩深夜福利久久| 久久夜色精品国产噜噜亚洲a| 色综合久久久久久久久五月| 久久精品国产亚洲一区二区| 久久亚洲精品人成综合网| 国产AV影片久久久久久| 久久99九九国产免费看小说| 精品久久久久久亚洲| 亚洲欧美成人久久综合中文网 | 2020久久精品亚洲热综合一本| 精品久久久久久成人AV|