Lake Counting
Time Limit:1000MS? Memory Limit:65536K
Total Submit:1360 Accepted:629
Description
Due to recent rains, water has pooled in various places in Farmer John's field, which is represented by a rectangle of N x M (1 <= N <= 100; 1 <= M <= 100) squares. Each square contains either water ('W') or dry land ('.'). Farmer John would like to figure out how many ponds have formed in his field. A pond is a connected set of squares with water in them, where a square is considered adjacent to all eight of its neighbors.
Given a diagram of Farmer John's field, determine how many ponds he has.
Input
* Line 1: Two space-separated integers: N and M
* Lines 2..N+1: M characters per line representing one row of Farmer John's field. Each character is either 'W' or '.'. The characters do not have spaces between them.
Output
* Line 1: The number of ponds in Farmer John's field.
Sample Input
10 12
W........WW.
.WWW.....WWW
....WW...WW.
.........WW.
.........W..
..W......W..
.W.W.....WW.
W.W.W.....W.
.W.W......W.
..W.......W.
Sample Output
3
Hint
OUTPUT DETAILS:
There are three ponds: one in the upper left, one in the lower left,and one along the right side.
Source
USACO 2004 November
#include?
<
iostream
>
using
?
namespace
?std;

const
?
int
?MAX?
=
?
102
;
int
?g[MAX][MAX];

void
?travel(
int
?i,?
int
?j)

{

????
int
?incr[
8
][
2
]?
=
?
{
{
0
,
-
1
}
,?
{
1
,
-
1
}
,?
{
1
,
0
}
,?
{
1
,
1
}
,?
{
0
,
1
}
,?
{
-
1
,
1
}
,?
{
-
1
,
0
}
,?
{
-
1
,
-
1
}
}
;
????
int
?k;
????
int
?tmpI,?tmpJ;

????
for
?(k
=
0
;?k
<
8
;?k
++
)?
{
????????tmpI?
=
?i?
+
?incr[k][
0
];
????????tmpJ?
=
?j?
+
?incr[k][
1
];

????????
if
?(g[tmpI][tmpJ]?
==
?
1
)?
{
????????????g[tmpI][tmpJ]?
=
?
-
1
;
????????????travel(tmpI,?tmpJ);
????????}
????}
}
int
?main()

{
????
int
?n,?m;
????
int
?i,?j;
????
int
?ans?
=
?
0
;
????
char
?t;
????cin?
>>
?n?
>>
?m;

????
for
?(i
=
0
;?i
<=
m
+
1
;?i
++
)?
{
????????g[
0
][i]?
=
?
-
1
;
????????g[n
+
1
][i]?
=
?
-
1
;
????}
????
for
?(i
=
0
;?i
<=
n
+
1
;?i
++
)?
{
????????g[i][
0
]?
=
?
-
1
;
????????g[i][m
+
1
]?
=
?
-
1
;
????}
????
for
?(i
=
1
;?i
<=
n;?i
++
)?
{

????????
for
?(j
=
1
;?j
<=
m;?j
++
)?
{
????????????cin?
>>
?t;

????????????
if
?(t?
==
?
'
W
'
)?
{
????????????????g[i][j]?
=
?
1
;

????????????}
?
else
?
{
????????????????g[i][j]?
=
?
0
;
????????????}
????????}
????}
????
for
?(i
=
1
;?i
<=
n;?i
++
)?
{

????????
for
?(j
=
1
;?j
<=
m;?j
++
)?
{

????????????
if
?(g[i][j]?
==
?
1
)?
{
????????????????ans
++
;
????????????????g[i][j]?
=
?
-
1
;
????????????????travel(i,?j);
????????????}
????????}
????}
????cout?
<<
?ans?
<<
?endl;
????
return
?
0
;
}
感受遞歸的神奇!
posted on 2006-05-01 18:48
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