• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            posts - 7,comments - 3,trackbacks - 0
            Slim Span
            Time Limit: 5000MSMemory Limit: 65536K
            Total Submissions: 4023Accepted: 2116

            Description

            Given an undirected weighted graph G, you should find one of spanning trees specified as follows.

            The graph G is an ordered pair (VE), where V is a set of vertices {v1v2, …, vn} and E is a set of undirected edges {e1e2, …, em}. Each edge e ∈ E has its weight w(e).

            A spanning tree T is a tree (a connected subgraph without cycles) which connects all the n vertices with n − 1 edges. The slimness of a spanning tree T is defined as the difference between the largest weight and the smallest weight among the n − 1 edges of T.


            Figure 5: A graph G and the weights of the edges

            For example, a graph G in Figure 5(a) has four vertices {v1v2v3v4} and five undirected edges {e1e2e3e4e5}. The weights of the edges are w(e1) = 3, w(e2) = 5, w(e3) = 6, w(e4) = 6, w(e5) = 7 as shown in Figure 5(b).


            Figure 6: Examples of the spanning trees of G

            There are several spanning trees for G. Four of them are depicted in Figure 6(a)~(d). The spanning tree Ta in Figure 6(a) has three edges whose weights are 3, 6 and 7. The largest weight is 7 and the smallest weight is 3 so that the slimness of the tree Ta is 4. The slimnesses of spanning trees TbTc and Td shown in Figure 6(b), (c) and (d) are 3, 2 and 1, respectively. You can easily see the slimness of any other spanning tree is greater than or equal to 1, thus the spanning tree Td in Figure 6(d) is one of the slimmest spanning trees whose slimness is 1.

            Your job is to write a program that computes the smallest slimness.

            Input

            The input consists of multiple datasets, followed by a line containing two zeros separated by a space. Each dataset has the following format.

            nm
            a1b1w1
            ambmwm

            Every input item in a dataset is a non-negative integer. Items in a line are separated by a space. n is the number of the vertices and m the number of the edges. You can assume 2 ≤ n ≤ 100 and 0 ≤ m ≤ n(n − 1)/2. ak and bk (k = 1, …, m) are positive integers less than or equal to n, which represent the two vertices vak and vbk connected by the kth edge ekwk is a positive integer less than or equal to 10000, which indicates the weight of ek. You can assume that the graph G = (VE) is simple, that is, there are no self-loops (that connect the same vertex) nor parallel edges (that are two or more edges whose both ends are the same two vertices).

            Output

            For each dataset, if the graph has spanning trees, the smallest slimness among them should be printed. Otherwise, −1 should be printed. An output should not contain extra characters.

            Sample Input

            4 5
            1 2 3
            1 3 5
            1 4 6
            2 4 6
            3 4 7
            4 6
            1 2 10
            1 3 100
            1 4 90
            2 3 20
            2 4 80
            3 4 40
            2 1
            1 2 1
            3 0
            3 1
            1 2 1
            3 3
            1 2 2
            2 3 5
            1 3 6
            5 10
            1 2 110
            1 3 120
            1 4 130
            1 5 120
            2 3 110
            2 4 120
            2 5 130
            3 4 120
            3 5 110
            4 5 120
            5 10
            1 2 9384
            1 3 887
            1 4 2778
            1 5 6916
            2 3 7794
            2 4 8336
            2 5 5387
            3 4 493
            3 5 6650
            4 5 1422
            5 8
            1 2 1
            2 3 100
            3 4 100
            4 5 100
            1 5 50
            2 5 50
            3 5 50
            4 1 150
            0 0

            Sample Output

            1
            20
            0
            -1
            -1
            1
            0
            1686
            50

            Source



            題目就是生成一棵樹,要求邊權最大減最小的差最小。
            根據Kruskal思想,把邊排序,之后枚舉一下就行了。

            代碼:

            #include <cmath>
            #include 
            <cstdio>
            #include 
            <cstdlib>
            #include 
            <cstring>
            #include 
            <iostream>
            #include 
            <algorithm>
            using namespace std;

            const int M = 5005;
            const int INF = 1 << 29;

            struct edge
            {
                
            int st, ed, w;
                
            bool operator < (edge a) const
                {
                    
            return w < a.w;
                }
            } e[M];

            int n, m, ans, num, temp;
            int f[105], rank[105];

            void makeset()
            {
                
            for (int i = 1; i <= n; ++i)
                    f[i] 
            = i;
                memset(rank, 
            0sizeof(rank));
            }

            int find(int x)
            {
                
            while (f[x] != x) x = f[x];
                
            return x;
            }

            void unionset(int a, int b)
            {
                
            int p = find(a);
                
            int q = find(b);
                
            if (rank[p] > rank[q])
                    f[q] 
            = p;
                
            else
                
            if (rank[p] < rank[q])
                    f[p] 
            = q;
                
            else
                {
                    f[p] 
            = q;
                    rank[q]
            ++;
                }
            }

            void kruskal()
            {
                ans 
            = INF;
                
            for (int i = 0; i < m - n + 2++i)
                {
                    makeset();
                    temp 
            = -1;
                    num 
            = 0;
                    
            for (int j = i; j < m; ++j)
                    {
                        
            if (find(e[j].st) != find(e[j].ed))
                        {
                            num
            ++;
                            unionset(e[j].st, e[j].ed);
                            
            if (num == n - 1)
                            {
                                temp 
            = e[j].w - e[i].w;
                                
            break;
                            }
                        }
                    }
                    
            if (temp == -1break;
                    
            if (temp != -1 && temp < ans) ans = temp;
                }
                
            if (ans >= INF) printf("-1\n");
                
            else printf("%d\n", ans);
            }

            int main()
            {
                
            while (scanf("%d%d"&n, &m), n || m)
                {
                    
            for (int i = 0; i < m; ++i)
                        scanf(
            "%d%d%d"&e[i].st, &e[i].ed, &e[i].w);
                    sort(e, e 
            + m);
                    kruskal();
                }
                
            return 0;
            }
            posted on 2011-10-17 15:54 LLawliet 閱讀(362) 評論(0)  編輯 收藏 引用 所屬分類: 圖論
            久久99精品国产麻豆宅宅| 国产精品嫩草影院久久| 亚洲欧洲久久av| 国产美女亚洲精品久久久综合| 影音先锋女人AV鲁色资源网久久| 久久亚洲精精品中文字幕| 久久久老熟女一区二区三区| 美女写真久久影院| 久久久国产视频| 久久精品国产福利国产秒| 久久久久99精品成人片牛牛影视| 久久久久无码精品国产app| 久久精品国产乱子伦| 青青青国产成人久久111网站| 欧美精品福利视频一区二区三区久久久精品 | 99久久精品免费| 亚洲午夜久久久久久噜噜噜| 久久香蕉综合色一综合色88| 久久精品日日躁夜夜躁欧美| 久久99精品国产一区二区三区| 久久天天躁狠狠躁夜夜2020一 | 伊人久久大香线蕉av不卡| 日本一区精品久久久久影院| 久久狠狠爱亚洲综合影院| 国产巨作麻豆欧美亚洲综合久久 | 99久久精品国产高清一区二区| 亚洲国产婷婷香蕉久久久久久| 久久国产高清字幕中文| 久久综合狠狠综合久久| 武侠古典久久婷婷狼人伊人| 久久福利片| 久久久久人妻精品一区三寸蜜桃 | 精品免费久久久久久久| 久久精品国产2020| 久久精品国产亚洲av水果派| 久久久精品午夜免费不卡| 久久久91人妻无码精品蜜桃HD| 91精品国产高清久久久久久io | 久久精品不卡| 精品久久久久久无码中文字幕| 亚洲国产精品久久久久久|