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Posted on 2009-03-25 18:07 besterChen 閱讀(2775) 評論(3) 編輯 收藏 引用 所屬分類: C/C++/STL/boost
比賽的地址是： http://www.ghoffice.com/bbs/read-htm-fid-97-tid-63475.html引用一下原題目：
很簡單的題目，可是要求是：要不你精簡，要不你奇特，我看到這個比賽題目的時候，沒有辦法，人家已經(jīng)把我知道的精簡式的代碼幾乎貼完了，那我也就只能來個奇特的了，用shellcode實現(xiàn)，代碼如下：
#include "stdio.h"
#include "windows.h"
typedef unsigned char BYTE;
typedef VOID (CALLBACK *MYSPRINTF)(char *, const char *,  );
typedef VOID (CALLBACK *MYLSTRCAT)(char *, char *);
typedef VOID (CALLBACK *MYMSGBOX)(HWND hWnd, LPCSTR lpText, LPCSTR lpCaption, UINT uType);
MYSPRINTF mySprintf = (MYSPRINTF)GetProcAddress(LoadLibraryA("msvcr71.dll"), "sprintf");
MYLSTRCAT myStrCat = (MYLSTRCAT)GetProcAddress(LoadLibraryA("KERNEL32.dll"), "lstrcatA");
MYMSGBOX myMsgBox = (MYMSGBOX)GetProcAddress(LoadLibraryA("user32.dll"), "MessageBoxA");
BYTE buf[] = { 0xB8,0x00,0x12,0x00,0x00,0xE8,0xAE,0x00,0x00,0x00,0x55,0x56,0x57,0xB9,0x7F,0x00,\
0x00,0x00,0x33,0xC0,0x8D,0x7C,0x24,0x0D,0xC6,0x44,0x24,0x0C,0x00,0xC6,0x84,0x24,\
0x0C,0x02,0x00,0x00,0x00,0xF3,0xAB,0x66,0xAB,0xAA,0xB9,0xFF,0x03,0x00,0x00,0x33,\
0xC0,0x8D,0xBC,0x24,0x0D,0x02,0x00,0x00,0xBE,0x01,0x00,0x00,0x00,0xF3,0xAB,0x66,\
0xAB,0xAA,0xBF,0x01,0x00,0x00,0x00,0x3B,0xF7,0x7C,0x33,0x8B,0xEE,0xA1,0x18,0x61,\
0x40,0x00,0x55,0x57,0x56,0x8D,0x4C,0x24,0x18,0x50,0x51,0xFF,0x15,0x20,0x86,0x40,\
0x00,0x83,0xC4,0x14,0x8D,0x54,0x24,0x0C,0x8D,0x84,0x24,0x0C,0x02,0x00,0x00,0x52,\
0x50,0xFF,0x15,0x28,0x86,0x40,0x00,0x47,0x03,0xEE,0x3B,0xFE,0x7E,0xCF,0x8D,0x8C,\
0x24,0x0C,0x02,0x00,0x00,0x68,0x24,0x61,0x40,0x00,0x51,0xFF,0x15,0x28,0x86,0x40,\
0x00,0x46,0x83,0xFE,0x0A,0x7C,0xAB,0x6A,0x00,0x8D,0x94,0x24,0x10,0x02,0x00,0x00,\
0x68,0x28,0x61,0x40,0x00,0x52,0x6A,0x00,0xFF,0x15,0x24,0x86,0x40,0x00,0x5F,0x5E,\
0x5D,0x81,0xC4,0x00,0x12,0x00,0x00,0xC3\
};
BYTE AllocBuf[] = { 0x51,0x3D,0x00,0x10,0x00,0x00,0x8D,0x4C,0x24,0x08,\
0x72,0x14,0x81,0xE9,0x00,0x10,0x00,0x00,0x2D,0x00,\
0x10,0x00,0x00,0x85,0x01,0x3D,0x00,0x10,0x00,0x00,\
0x73,0xEC,0x2B,0xC8,0x8B,0xC4,0x85,0x01,0x8B,0xE1,\
0x8B,0x08,0x8B,0x40,0x04,0x50,0xC3\
};
const char *pConChar = "%d*%d=%-4d\0";
const char *pTitle = "九九乘法表\0";
char *pNchar = "\n";
void main()
{
long* pVoid = (long *)buf;
__asm
{
CALL pVoid;
}
}
就這樣了，貼小效果的圖片吧：  貼一下bin和SRC: bin和Src (說明，由于全部用了硬編碼，所以，有可能在各位的電腦上不能正常運行！) MS：本程序在WinXP SP3下測試通過！
Feedback
# re: 廣海社區(qū) --- 編程大塞題目《打印九九乘法表》 回復 更多評論
2009-03-26 19:28 by
其實有一種方法 有效率又很小
# re: 廣海社區(qū) --- 編程大塞題目《打印九九乘法表》[未登錄] 回復 更多評論
2010-01-13 08:04 by
小論壇吧。
# re: 廣海社區(qū) --- 編程大塞題目《打印九九乘法表》 回復 更多評論
2012-01-10 10:45 by
胖子這么變態(tài)。。。
puts("1x1=1");
.....
puts("9x9=81");
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