• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>

            oyjpArt ACM/ICPC算法程序設計空間

            // I am new in programming, welcome to my blog
            I am oyjpart(alpc12, 四城)
            posts - 224, comments - 694, trackbacks - 0, articles - 6

            終于發現自己G題Accelarator的錯誤了 找了好久好久 就這個錯誤 讓我在整個后半段的比賽中幾乎廢掉了 太不應該了!
            吸取教訓!在場上出現自己無法找出錯誤的情況 應該要讓隊友重寫

            #include <stdio.h>
            #include <string.h>
            #include <math.h>

            const int N = 100010;
            int d[N];
            __int64 d2[N];
            int na, av, np;

            bool check(int x) {
             int i;
             for(i = 0; i < np; i++) d2[i] = d[i];
             for(i = 0; i < np; i++) d2[i] -= x;
             int cnt = 0;
             __int64 rest = na*x; 左邊寫了__int64 右邊卻忘記轉成__int64了
             for(i = 0; i<np; i++) {
              if(d2[i] > 0) {
               if(av <= 0) return false;
               __int64 need = (d2[i]-1)/av + 1;
               if(need > rest || need > x) return false;
               rest -= need;
              }
             }
             return 1;
            }

            int main() {
             int ntc, i;
             scanf("%d", &ntc);
             while(ntc--) {
              scanf("%d", &np);
              int _max = -1;
              for(i = 0; i<np; i++) {
               scanf("%d", d + i);
               if(d[i] > _max) _max = d[i];
              }
              scanf("%d %d", &na, &av);
              av--;
              int lo = 0, hi = _max;
              while(lo < hi) {
               int mid = lo + (hi-lo)/2;
               if(check(mid)) hi = mid;
               else lo = mid+1;
              }
              if(check(lo)) printf("%d\n", lo);
             }
             return 0;
            }

              
            Accelerator
            Time Limit:4000MS  Memory Limit:65536K
            Total Submit:811 Accepted:142

            Description


            Shiming (alpc02) is a boy likes to play PopKart very much. He is a good rider in this game. And one day he thought that he became a team leader of a team of N Kart riders.

            Today, after the game begins, the riders of his team are now at different places at the racetrack, for that some of the riders got some short cut.

            However, we know actually how long has each rider left to run along, and they will ride actually one meter per one time unit (maybe 10ms).

            Luckily, Shiming now gets M accelerators, the accelerator can help one rider to ride k meters per one time unit. And all the accelerators are as the same. But one rider can't use more than one accelerator at one time unit.

            Shiming is the team leader, and he wants all the team members to finish in the minimal time not just the fastest one to finish the race. He will distribute all the accelerators to the riders.

            Note: Here some rules are not as the same as the game we played. At a time unit, Shiming distributes the accelerators to riders for one rider one accelerator, and at the next time unit, all the accelerator can be reused, and Shiming can re-distributes all the accelerators to riders also for one rider one accelerator and the distribution is no relationship with the last time unit.

            So you will program to help Shiming to get the actually minimal time the team will use to finish the race.


            Input


            The input file has T (1<T<20) test cases, and the first line of the file will show the T.

            Each of test cases, will be the N (1<= N <= 100000) rider, and N numbers Ai (1<= Ai <= 10^8) show how long will the rider have to finish the race. And the M and the K (1<= K*M <=10^8) for the accelerators.


            Output
            For each of test cases print a single integer on a single line, the minimal possible number of time units required to finish the race all team.

            Sample Input


            2
            3
            2 3 9
            1 5
            3
            2 3 6
            1 5


            Sample Output


            3
            2

            Feedback

            # re: 終于發現自己G題Accelarator的錯誤了  回復  更多評論   

            2007-05-10 22:29 by
            bless,我也是錯在這個上。

            # re: 終于發現自己G題Accelarator的錯誤了  回復  更多評論   

            2007-05-11 12:25 by oyjpart
            這么巧啊 同bless
            久久精品aⅴ无码中文字字幕不卡| AAA级久久久精品无码区| 午夜肉伦伦影院久久精品免费看国产一区二区三区 | 91精品免费久久久久久久久| 午夜不卡888久久| 欧美伊人久久大香线蕉综合69| 亚洲日本久久久午夜精品| 97精品国产97久久久久久免费| 国产精品欧美久久久天天影视| 国产福利电影一区二区三区久久久久成人精品综合| 99久久综合狠狠综合久久止| 人妻精品久久久久中文字幕| 亚洲伊人久久大香线蕉综合图片 | 亚洲欧美一级久久精品| 青青草原精品99久久精品66| 久久亚洲精品视频| 色欲久久久天天天综合网| 99久久精品免费观看国产| 囯产精品久久久久久久久蜜桃| 青青青青久久精品国产 | 久久影视国产亚洲| 久久国产精品无码一区二区三区 | 久久99久久99精品免视看动漫| 国产美女久久精品香蕉69| 久久久噜噜噜久久| 久久精品国产91久久麻豆自制| 欧美国产成人久久精品| 理论片午午伦夜理片久久| 色综合久久综合网观看| 国产精品美女久久久m| 中文字幕无码av激情不卡久久| 国产精品久久久99| 999久久久免费国产精品播放| 精品久久一区二区三区| 波多野结衣中文字幕久久| 亚洲国产精品无码久久久秋霞2 | 久久av无码专区亚洲av桃花岛| 精品久久久久成人码免费动漫| 亚洲综合久久夜AV | 欧美亚洲国产精品久久久久| 午夜视频久久久久一区 |