Posted on 2006-11-08 13:32
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項目需要，寫了一個幫助L10N的工程師計算utf8的小工具(html page)。如下
<!DOCTYPE?HTML?PUBLIC?"-//W3C//DTD?HTML?4.0?Transitional//EN">
<HTML>
<HEAD>
<TITLE>?An?utf8?count?tool??</TITLE>
<meta?http-equiv="Content-Type"?content="text/html;?charset=utf16">
<script>
????function?utf16to8(str)?{
????????var?out,?i,?len,?c;
????????out?=?"";
????????len?=?str.length;
????????for(i?=?0;?i?<?len;?i++)?{
????????c?=?str.charCodeAt(i);
????????if?((c?>=?0x0001)?&&?(c?<=?0x007F))?{
????????????out?+=?str.charAt(i);
????????}?else?if?(c?>?0x07FF)?{
????????????out?+=?String.fromCharCode(0xE0?|?((c?>>?12)?&?0x0F));
????????????out?+=?String.fromCharCode(0x80?|?((c?>>??6)?&?0x3F));
????????????out?+=?String.fromCharCode(0x80?|?((c?>>??0)?&?0x3F));
????????}?else?{
????????????out?+=?String.fromCharCode(0xC0?|?((c?>>??6)?&?0x1F));
????????????out?+=?String.fromCharCode(0x80?|?((c?>>??0)?&?0x3F));
????????}
????????}
????????return?out;
????}
????function?count()
????{
????????var?temp?=?f1.value;
????????temp=temp.replace(/\\r/g,"\r");
????????temp=temp.replace(/\\n/g,"\n");
????????result.innerHTML=utf16to8(temp).length;
????}
</script>
</HEAD>
<BODY>
<TEXTAREA?id="f1"?NAME="f1"?ROWS="10"?COLS="50"></TEXTAREA>
<br/>
<INPUT?TYPE="button"?value="count?length"?onclick="count()">
<div?id="result"></div>
</BODY>
</HTML>