青青草原综合久久大伊人导航_色综合久久天天综合_日日噜噜夜夜狠狠久久丁香五月_热久久这里只有精品

技術,瞎侃,健康,休閑……

mahu@cppblog 人類的全部才能無非是時間和耐心的混合物
posts - 11, comments - 13, trackbacks - 0, articles - 12
  C++博客 :: 首頁 :: 新隨筆 :: 聯(lián)系 :: 聚合  :: 管理

The Blocks Problem

Posted on 2006-06-10 01:16 mahudu@cppblog 閱讀(910) 評論(1)  編輯 收藏 引用 所屬分類: C/C++

Background?

Many areas of Computer Science use simple, abstract domains for both analytical and empirical studies. For example, an early AI study of planning and robotics (STRIPS) used a block world in which a robot arm performed tasks involving the manipulation of blocks.

In this problem you will model a simple block world under certain rules and constraints. Rather than determine how to achieve a specified state, you will ``program'' a robotic arm to respond to a limited set of commands.

The Problem?

The problem is to parse a series of commands that instruct a robot arm in how to manipulate blocks that lie on a flat table. Initially there are n blocks on the table (numbered from 0 to n-1) with block bi adjacent to block bi+1 for all $0 \leq i < n-1$ as shown in the diagram below:
?
\begin{figure}
\centering
\setlength{\unitlength}{0.0125in} %
\begin{picture}
(2...
...raisebox{0pt}[0pt][0pt]{$\bullet
\bullet \bullet$ }}}
\end{picture}
\end{figure}
Figure: Initial Blocks World

The valid commands for the robot arm that manipulates blocks are:

  • move a onto b

    where a and b are block numbers, puts block a onto block b after returning any blocks that are stacked on top of blocks a and b to their initial positions.

  • move a over b

    where a and b are block numbers, puts block a onto the top of the stack containing block b, after returning any blocks that are stacked on top of block a to their initial positions.

  • pile a onto b

    where a and b are block numbers, moves the pile of blocks consisting of block a, and any blocks that are stacked above block a, onto block b. All blocks on top of block b are moved to their initial positions prior to the pile taking place. The blocks stacked above block a retain their order when moved.

  • pile a over b

    where a and b are block numbers, puts the pile of blocks consisting of block a, and any blocks that are stacked above block a, onto the top of the stack containing block b. The blocks stacked above block a retain their original order when moved.

  • quit

    terminates manipulations in the block world.

Any command in which a = b or in which a and b are in the same stack of blocks is an illegal command. All illegal commands should be ignored and should have no affect on the configuration of blocks.

The Input?

The input begins with an integer n on a line by itself representing the number of blocks in the block world. You may assume that 0 < n < 25.

The number of blocks is followed by a sequence of block commands, one command per line. Your program should process all commands until the quit command is encountered.

You may assume that all commands will be of the form specified above. There will be no syntactically incorrect commands.

The Output?

The output should consist of the final state of the blocks world. Each original block position numbered i ( $0 \leq i < n$ where n is the number of blocks) should appear followed immediately by a colon. If there is at least a block on it, the colon must be followed by one space, followed by a list of blocks that appear stacked in that position with each block number separated from other block numbers by a space. Don't put any trailing spaces on a line.

There should be one line of output for each block position (i.e., n lines of output where n is the integer on the first line of input).

Sample Input?

10
move 9 onto 1
move 8 over 1
move 7 over 1
move 6 over 1
pile 8 over 6
pile 8 over 5
move 2 over 1
move 4 over 9
quit

Sample Output?

 0: 0
1: 1 9 2 4
2:
3: 3
4:
5: 5 8 7 6
6:
7:
8:
9:

Solution

#include?<stdio.h>
#define?MAXB?100?????????????????????/*?maximum?number?of?blocks?*/
????
typedef?
struct?block{
????
struct?block?*above;
????
struct?block?*below;
????
int?index;
}
?block;

block?blocks[MAXB];??????????????????
/*?storage?for?the?blocks?*/
block?
*table[MAXB];??????????????????/*?pointers?to?each?block?*/
int?numBlocks;?????????????????????????/*?the?actual?number?of?blocks?*/


void?InitBlocks()
/*?initially?table[i]?-->?blocks[i],?one?block?per?stack?*/?????
{
????
int?i;
????
for(i=0;i<numBlocks;i++){
????blocks[i].index?
=?i;
????blocks[i].above?
=?(block?*)?NULL;
????blocks[i].below?
=?(block?*)?NULL;
????table[i]?
=?&blocks[i];
????}

}



block?
*BlockTop(int?n)
/*?return?a?pointer?to?the?block?on?top?of?the?stack?in?which?block?*/
/*?n?is?located?*/?????
{
????block?
*temp?=?table[n];

????
while?(temp->above?!=?(block?*)?NULL){
????temp?
=?temp->above;
????}

????
return?temp;
}



void?ClearStackAbove(int?n)
/*?return?all?blocks?stacked?above?block?n?to?their?original?spot?*/?????
{
????block?
*top,*next;

????top?
=?BlockTop(n);
????
while?(top?!=?table[n]){??????/*?until?we?reach?block?n?*/
????next?
=?top->below;

????
/*?unlink?block?from?stack?*/
????top
->above?=?(block?*)?NULL;
????top
->below?=?(block?*)?NULL;
????
????top?
=?next;
????}

????table[n]
->above?=?(block?*)?NULL;
}


void?MoveOnto(int?n,int?k)
{
????ClearStackAbove(n);
????ClearStackAbove(k);
????table[k]
->above?=?table[n];????????/*?move?n?onto?k?*/
????
if?(table[n]->below)??????????????/*?be?safe?when?relinking?*/
????table[n]
->below->above?=?(block?*)?NULL;
????table[n]
->below?=?table[k];
}


void?PileOnto(int?n,int?k)
{
????ClearStackAbove(k);
????table[k]
->above?=?table[n];????????????/*?move?n?onto?k??*/
????
if?(table[n]->below)????????/*?be?safe?when?relinking?*/
????table[n]
->below->above?=?(block?*)?NULL;
????table[n]
->below?=?table[k];
}


int?IsOver(int?n,int?k)
/*?return?1?if?block?n?is?"over"?block?k?(same?stack),?else?0?*/?????
{
????block?
*temp;

????temp?
=?table[k];
????
while?(temp){
????
if?(temp->index?==?n)
????????
return?1;
????temp?
=?temp->above;
????}

????
return?0;
}


????
void?MoveOver(int?n,int?k)
{
????block?
*top;
????
????ClearStackAbove(n);
????top?
=?BlockTop(k);????????????/*?top?of?block?k's?stack?*/
????top
->above?=?table[n];
????
if?(table[n]->below)????????????/*?be?safe?when?relinking?*/
????table[n]
->below->above?=?(block?*)?NULL;
????table[n]
->below?=?top;
}


void?PileOver(int?n,int?k)
{
????block?
*top;
????
????top?
=?BlockTop(k);????????????/*?top?of?block?k's?stack?*/
????top
->above?=?table[n];????
????
if?(table[n]->below)????????????/*?be?safe?when?relinking?*/
????table[n]
->below->above?=?(block?*)?NULL;????
????table[n]
->below?=?top;
}


main()
{

????
char?ch;
????
int?n,k;
????block?
*bottom;
????
char?b1[10],b2[10];???????????????/*?b1?=?move/pile,?b2?=?onto/over?*/
????
char?*w1?=?&b1[0];
????
char?*w2?=?&b2[0];

????scanf(
"%d\n",&numBlocks);
????InitBlocks();
????
while?(1){
????scanf(
"%s",w1);
????
if?(w1[0]?==?'q')???/*?quit??*/
????????
break;
????scanf(
"%d?%s?%d\n",&n,w2,&k);

????
/*?is?command?a?legal?command??*/
????
if?(n?==?k?||?IsOver(k,n)?||?IsOver(n,k)){
????????
continue;
????}

????
????
switch?(w1[0]){
??????
case?'m':
????????
switch?(w2[1]){
??????????
case?'n':????/*?onto?*/
????????MoveOnto(n,k);
????????
break;
??????????
case?'v':????/*?over?*/
????????MoveOver(n,k);
????????
break;
??????????
default:
????????fprintf(stderr,
"illegal?command?%s\n",w2);
????????}

????????
break;
??????
case?'p':
????????
switch?(w2[1]){
??????????
case?'n':????/*?onto?*/
????????PileOnto(n,k);
????????
break;
??????????
case?'v':????/*?over?*/
????????PileOver(n,k);
????????
break;
??????????
default:
????????fprintf(stderr,
"illegal?command?%s\n",w2);
????????}

????????
break;
??????
default:
????????fprintf(stderr,
"illegal?command?%s\n",w2);
????}

????}


????
/*?print?stacks?*/
????
????
for(k=0;k<numBlocks;k++){
????printf(
"%2d:?",k);

????
/*?is?block?in?another?stack?,?if?so,?nothing?to?print?*/
????
????
if?(table[k]->below?!=?(block?*)?NULL){
????????printf(
"\n");
????}

????
else{
????????bottom?
=?table[k];
????????
while?(bottom){
????????printf(
"?%d",bottom->index);
????????bottom?
=?bottom->above;
????????}

????????printf(
"\n");
????}

????}

????
}

Feedback

# re: The Blocks Problem[未登錄]  回復  更多評論   

2007-05-31 16:05 by Joe
最近在做電子商務的翻譯,不知道The Blocks Problem 是什么意思?怎么這里也沒有中文解釋啊!好不郁悶!
青青草原综合久久大伊人导航_色综合久久天天综合_日日噜噜夜夜狠狠久久丁香五月_热久久这里只有精品
  • <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            久久久久久久精| 欧美在线一二三四区| 韩国三级电影久久久久久| 亚洲电影免费观看高清| 国产精品入口66mio| 亚洲高清一二三区| 韩日欧美一区二区三区| 亚洲午夜精品网| 亚洲美女毛片| 浪潮色综合久久天堂| 性亚洲最疯狂xxxx高清| 欧美日韩国产精品专区| 亚洲黄色影片| 亚洲国产另类精品专区| 久久精品人人做人人爽| 久久精品国产一区二区三区免费看| 欧美日韩黄色一区二区| 亚洲黄色成人网| 91久久精品一区| 美女日韩欧美| 亚洲第一天堂av| 亚洲高清视频在线| 久久久久亚洲综合| 久久影视精品| 在线欧美一区| 噜噜噜噜噜久久久久久91| 猛男gaygay欧美视频| 影音先锋久久久| 美女国产一区| 亚洲国产91| 亚洲精品美女久久久久| 欧美精品三级| 一本色道久久综合亚洲91| 亚洲无限av看| 国产精品大全| 亚洲欧美日本另类| 久久久www成人免费毛片麻豆| 国产在线播精品第三| 久久精品一本| 欧美国产日韩二区| 99精品福利视频| 欧美性视频网站| 欧美一区二区国产| 免费成人黄色| 日韩一二三区视频| 国产精品欧美一区二区三区奶水| 亚洲欧美一区二区视频| 美腿丝袜亚洲色图| 夜夜嗨av一区二区三区四季av| 欧美午夜精品理论片a级按摩 | 亚洲黄色在线观看| 亚洲视频日本| 国产综合视频在线观看| 久久亚洲欧美| 99视频国产精品免费观看| 欧美中文字幕在线| 亚洲经典在线看| 国产精品视频一区二区三区| 欧美在线免费播放| 亚洲国产日韩综合一区| 性做久久久久久久免费看| 一色屋精品视频免费看| 欧美精品一区二区三区久久久竹菊 | 亚洲自拍偷拍网址| 在线精品国产成人综合| 欧美日韩美女在线观看| 午夜精品久久久久久久99水蜜桃| 乱人伦精品视频在线观看| 一区二区三区国产精华| 国内成人精品2018免费看| 欧美精品乱码久久久久久按摩| 一区二区三区**美女毛片| 免费不卡在线视频| 亚洲女爱视频在线| 亚洲精品一区在线观看| 国产精品欧美日韩久久| 欧美激情精品久久久久久黑人| 亚洲欧美视频在线| 亚洲国语精品自产拍在线观看| 久久国产欧美| 一区二区三区欧美在线观看| 国产一区二区三区日韩| 欧美先锋影音| 免费一级欧美在线大片| 亚洲欧美日韩国产成人精品影院| 亚洲高清资源综合久久精品| 久久精品国产清高在天天线 | 国产精品99久久99久久久二8| 国产美女精品视频免费观看| 牛牛影视久久网| 久久福利影视| 性欧美videos另类喷潮| 99国产一区| 亚洲国产三级在线| 欧美成人免费网| 久久在线播放| 久久久久网址| 久久久久九九视频| 亚洲欧美精品在线| 中文欧美字幕免费| 在线视频你懂得一区| 亚洲精品视频在线观看网站| 亚洲高清二区| 激情综合网激情| 国产自产在线视频一区| 国产三级精品三级| 国产日韩av高清| 国产精品色在线| 国产精品久久久久国产精品日日| 欧美激情第二页| 欧美韩国日本一区| 欧美区在线播放| 欧美日韩岛国| 国产精品久久久久9999吃药| 欧美婷婷在线| 国产精品人人做人人爽人人添| 欧美日韩在线播| 欧美日韩国产综合一区二区| 欧美另类videos死尸| 欧美日韩国产在线播放网站| 欧美四级在线| 国产欧美日韩综合| 影音先锋亚洲一区| 亚洲经典在线看| 亚洲视频高清| 亚洲午夜电影| 性欧美video另类hd性玩具| 欧美在线视频观看| 老**午夜毛片一区二区三区| 亚洲第一级黄色片| 一本高清dvd不卡在线观看| 在线亚洲欧美专区二区| 午夜精品视频在线观看| 久久一区激情| 欧美日韩精品不卡| 国产亚洲激情视频在线| 亚洲人在线视频| 亚洲尤物视频在线| 久久亚洲一区二区| 亚洲精品视频一区| 亚洲免费影院| 欧美jizz19性欧美| 国产精品白丝av嫩草影院| 国产色婷婷国产综合在线理论片a| 红桃视频一区| aⅴ色国产欧美| 久久久久国产精品午夜一区| 欧美高清免费| 亚洲桃花岛网站| 久久亚洲综合| 国产精品美女久久久久aⅴ国产馆| 国语精品一区| 亚洲影院免费观看| 欧美福利在线| 欧美一级二级三级蜜桃| 男同欧美伦乱| 国产亚洲一区二区三区在线播放| 亚洲国产日韩欧美一区二区三区| 亚洲在线一区| 欧美黄色小视频| 午夜精品久久久久久久久久久久| 欧美α欧美αv大片| 国产欧美日韩在线| 中文国产成人精品| 欧美电影免费观看高清完整版| 亚洲——在线| 欧美日韩福利| 亚洲福利国产精品| 久久精品av麻豆的观看方式| 日韩午夜黄色| 欧美 日韩 国产 一区| 国产午夜久久| 亚洲欧美日韩一区二区三区在线| 免费成人av在线| 欧美一区二区三区在线| 国产精品激情av在线播放| 亚洲人成精品久久久久| 美女国产一区| 欧美在线关看| 国产区亚洲区欧美区| 在线中文字幕日韩| 亚洲国产一区二区三区在线播| 久久免费午夜影院| 国产综合在线视频| 久久激情五月激情| 性欧美8khd高清极品| 国产精品一区二区在线| 午夜精品久久| 亚洲一区久久久| 国产精品久久久久9999| 亚洲综合欧美日韩| 一区二区三区高清不卡| 欧美日韩视频在线一区二区观看视频 | 亚洲欧美综合v| 国产精品视频福利| 性欧美长视频| 欧美一级二级三级蜜桃| 国产真实久久| 男人的天堂亚洲在线| 美女91精品|