• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>

            技術,瞎侃,健康,休閑……

            mahu@cppblog 人類的全部才能無非是時間和耐心的混合物
            posts - 11, comments - 13, trackbacks - 0, articles - 12
              C++博客 :: 首頁 :: 新隨筆 :: 聯系 :: 聚合  :: 管理

            The Blocks Problem

            Posted on 2006-06-10 01:16 mahudu@cppblog 閱讀(879) 評論(1)  編輯 收藏 引用 所屬分類: C/C++

            Background?

            Many areas of Computer Science use simple, abstract domains for both analytical and empirical studies. For example, an early AI study of planning and robotics (STRIPS) used a block world in which a robot arm performed tasks involving the manipulation of blocks.

            In this problem you will model a simple block world under certain rules and constraints. Rather than determine how to achieve a specified state, you will ``program'' a robotic arm to respond to a limited set of commands.

            The Problem?

            The problem is to parse a series of commands that instruct a robot arm in how to manipulate blocks that lie on a flat table. Initially there are n blocks on the table (numbered from 0 to n-1) with block bi adjacent to block bi+1 for all $0 \leq i < n-1$ as shown in the diagram below:
            ?
            \begin{figure}
\centering
\setlength{\unitlength}{0.0125in} %
\begin{picture}
(2...
...raisebox{0pt}[0pt][0pt]{$\bullet
\bullet \bullet$ }}}
\end{picture}
\end{figure}
            Figure: Initial Blocks World

            The valid commands for the robot arm that manipulates blocks are:

            • move a onto b

              where a and b are block numbers, puts block a onto block b after returning any blocks that are stacked on top of blocks a and b to their initial positions.

            • move a over b

              where a and b are block numbers, puts block a onto the top of the stack containing block b, after returning any blocks that are stacked on top of block a to their initial positions.

            • pile a onto b

              where a and b are block numbers, moves the pile of blocks consisting of block a, and any blocks that are stacked above block a, onto block b. All blocks on top of block b are moved to their initial positions prior to the pile taking place. The blocks stacked above block a retain their order when moved.

            • pile a over b

              where a and b are block numbers, puts the pile of blocks consisting of block a, and any blocks that are stacked above block a, onto the top of the stack containing block b. The blocks stacked above block a retain their original order when moved.

            • quit

              terminates manipulations in the block world.

            Any command in which a = b or in which a and b are in the same stack of blocks is an illegal command. All illegal commands should be ignored and should have no affect on the configuration of blocks.

            The Input?

            The input begins with an integer n on a line by itself representing the number of blocks in the block world. You may assume that 0 < n < 25.

            The number of blocks is followed by a sequence of block commands, one command per line. Your program should process all commands until the quit command is encountered.

            You may assume that all commands will be of the form specified above. There will be no syntactically incorrect commands.

            The Output?

            The output should consist of the final state of the blocks world. Each original block position numbered i ( $0 \leq i < n$ where n is the number of blocks) should appear followed immediately by a colon. If there is at least a block on it, the colon must be followed by one space, followed by a list of blocks that appear stacked in that position with each block number separated from other block numbers by a space. Don't put any trailing spaces on a line.

            There should be one line of output for each block position (i.e., n lines of output where n is the integer on the first line of input).

            Sample Input?

            10
            move 9 onto 1
            move 8 over 1
            move 7 over 1
            move 6 over 1
            pile 8 over 6
            pile 8 over 5
            move 2 over 1
            move 4 over 9
            quit

            Sample Output?

             0: 0
            1: 1 9 2 4
            2:
            3: 3
            4:
            5: 5 8 7 6
            6:
            7:
            8:
            9:

            Solution

            #include?<stdio.h>
            #define?MAXB?100?????????????????????/*?maximum?number?of?blocks?*/
            ????
            typedef?
            struct?block{
            ????
            struct?block?*above;
            ????
            struct?block?*below;
            ????
            int?index;
            }
            ?block;

            block?blocks[MAXB];??????????????????
            /*?storage?for?the?blocks?*/
            block?
            *table[MAXB];??????????????????/*?pointers?to?each?block?*/
            int?numBlocks;?????????????????????????/*?the?actual?number?of?blocks?*/


            void?InitBlocks()
            /*?initially?table[i]?-->?blocks[i],?one?block?per?stack?*/?????
            {
            ????
            int?i;
            ????
            for(i=0;i<numBlocks;i++){
            ????blocks[i].index?
            =?i;
            ????blocks[i].above?
            =?(block?*)?NULL;
            ????blocks[i].below?
            =?(block?*)?NULL;
            ????table[i]?
            =?&blocks[i];
            ????}

            }



            block?
            *BlockTop(int?n)
            /*?return?a?pointer?to?the?block?on?top?of?the?stack?in?which?block?*/
            /*?n?is?located?*/?????
            {
            ????block?
            *temp?=?table[n];

            ????
            while?(temp->above?!=?(block?*)?NULL){
            ????temp?
            =?temp->above;
            ????}

            ????
            return?temp;
            }



            void?ClearStackAbove(int?n)
            /*?return?all?blocks?stacked?above?block?n?to?their?original?spot?*/?????
            {
            ????block?
            *top,*next;

            ????top?
            =?BlockTop(n);
            ????
            while?(top?!=?table[n]){??????/*?until?we?reach?block?n?*/
            ????next?
            =?top->below;

            ????
            /*?unlink?block?from?stack?*/
            ????top
            ->above?=?(block?*)?NULL;
            ????top
            ->below?=?(block?*)?NULL;
            ????
            ????top?
            =?next;
            ????}

            ????table[n]
            ->above?=?(block?*)?NULL;
            }


            void?MoveOnto(int?n,int?k)
            {
            ????ClearStackAbove(n);
            ????ClearStackAbove(k);
            ????table[k]
            ->above?=?table[n];????????/*?move?n?onto?k?*/
            ????
            if?(table[n]->below)??????????????/*?be?safe?when?relinking?*/
            ????table[n]
            ->below->above?=?(block?*)?NULL;
            ????table[n]
            ->below?=?table[k];
            }


            void?PileOnto(int?n,int?k)
            {
            ????ClearStackAbove(k);
            ????table[k]
            ->above?=?table[n];????????????/*?move?n?onto?k??*/
            ????
            if?(table[n]->below)????????/*?be?safe?when?relinking?*/
            ????table[n]
            ->below->above?=?(block?*)?NULL;
            ????table[n]
            ->below?=?table[k];
            }


            int?IsOver(int?n,int?k)
            /*?return?1?if?block?n?is?"over"?block?k?(same?stack),?else?0?*/?????
            {
            ????block?
            *temp;

            ????temp?
            =?table[k];
            ????
            while?(temp){
            ????
            if?(temp->index?==?n)
            ????????
            return?1;
            ????temp?
            =?temp->above;
            ????}

            ????
            return?0;
            }


            ????
            void?MoveOver(int?n,int?k)
            {
            ????block?
            *top;
            ????
            ????ClearStackAbove(n);
            ????top?
            =?BlockTop(k);????????????/*?top?of?block?k's?stack?*/
            ????top
            ->above?=?table[n];
            ????
            if?(table[n]->below)????????????/*?be?safe?when?relinking?*/
            ????table[n]
            ->below->above?=?(block?*)?NULL;
            ????table[n]
            ->below?=?top;
            }


            void?PileOver(int?n,int?k)
            {
            ????block?
            *top;
            ????
            ????top?
            =?BlockTop(k);????????????/*?top?of?block?k's?stack?*/
            ????top
            ->above?=?table[n];????
            ????
            if?(table[n]->below)????????????/*?be?safe?when?relinking?*/
            ????table[n]
            ->below->above?=?(block?*)?NULL;????
            ????table[n]
            ->below?=?top;
            }


            main()
            {

            ????
            char?ch;
            ????
            int?n,k;
            ????block?
            *bottom;
            ????
            char?b1[10],b2[10];???????????????/*?b1?=?move/pile,?b2?=?onto/over?*/
            ????
            char?*w1?=?&b1[0];
            ????
            char?*w2?=?&b2[0];

            ????scanf(
            "%d\n",&numBlocks);
            ????InitBlocks();
            ????
            while?(1){
            ????scanf(
            "%s",w1);
            ????
            if?(w1[0]?==?'q')???/*?quit??*/
            ????????
            break;
            ????scanf(
            "%d?%s?%d\n",&n,w2,&k);

            ????
            /*?is?command?a?legal?command??*/
            ????
            if?(n?==?k?||?IsOver(k,n)?||?IsOver(n,k)){
            ????????
            continue;
            ????}

            ????
            ????
            switch?(w1[0]){
            ??????
            case?'m':
            ????????
            switch?(w2[1]){
            ??????????
            case?'n':????/*?onto?*/
            ????????MoveOnto(n,k);
            ????????
            break;
            ??????????
            case?'v':????/*?over?*/
            ????????MoveOver(n,k);
            ????????
            break;
            ??????????
            default:
            ????????fprintf(stderr,
            "illegal?command?%s\n",w2);
            ????????}

            ????????
            break;
            ??????
            case?'p':
            ????????
            switch?(w2[1]){
            ??????????
            case?'n':????/*?onto?*/
            ????????PileOnto(n,k);
            ????????
            break;
            ??????????
            case?'v':????/*?over?*/
            ????????PileOver(n,k);
            ????????
            break;
            ??????????
            default:
            ????????fprintf(stderr,
            "illegal?command?%s\n",w2);
            ????????}

            ????????
            break;
            ??????
            default:
            ????????fprintf(stderr,
            "illegal?command?%s\n",w2);
            ????}

            ????}


            ????
            /*?print?stacks?*/
            ????
            ????
            for(k=0;k<numBlocks;k++){
            ????printf(
            "%2d:?",k);

            ????
            /*?is?block?in?another?stack?,?if?so,?nothing?to?print?*/
            ????
            ????
            if?(table[k]->below?!=?(block?*)?NULL){
            ????????printf(
            "\n");
            ????}

            ????
            else{
            ????????bottom?
            =?table[k];
            ????????
            while?(bottom){
            ????????printf(
            "?%d",bottom->index);
            ????????bottom?
            =?bottom->above;
            ????????}

            ????????printf(
            "\n");
            ????}

            ????}

            ????
            }

            Feedback

            # re: The Blocks Problem[未登錄]  回復  更多評論   

            2007-05-31 16:05 by Joe
            最近在做電子商務的翻譯,不知道The Blocks Problem 是什么意思?怎么這里也沒有中文解釋啊!好不郁悶!
            奇米影视7777久久精品人人爽| 国产精品9999久久久久| 国产精品欧美久久久天天影视| 久久99精品国产麻豆宅宅| 久久久青草久久久青草| 久久精品国产色蜜蜜麻豆| 亚洲另类欧美综合久久图片区| 色88久久久久高潮综合影院 | 日韩精品久久久久久久电影| 亚洲av成人无码久久精品| 久久精品中文无码资源站| 热RE99久久精品国产66热| 久久久久亚洲精品无码蜜桃| 日韩欧美亚洲国产精品字幕久久久| 久久精品亚洲AV久久久无码| 国产午夜精品久久久久九九电影| 亚洲国产精品成人久久| 国产伊人久久| 久久99精品国产一区二区三区| 国产精品久久久久蜜芽| 久久播电影网| 国产福利电影一区二区三区久久久久成人精品综合 | 国产91久久综合| 久久国产色AV免费看| 久久精品综合网| 久久强奷乱码老熟女网站| 久久久久一区二区三区| 久久国产精品一国产精品金尊| 久久久久久国产精品美女| 日韩十八禁一区二区久久| 国产精品久久久久久久久鸭| 久久香蕉国产线看观看精品yw| 99久久综合国产精品免费| 久久天天日天天操综合伊人av| 精品国产一区二区三区久久蜜臀| 国产一级做a爰片久久毛片| 99久久精品国产麻豆| 久久精品国产亚洲一区二区| 88久久精品无码一区二区毛片| 欧美一区二区精品久久| 91精品国产91久久久久久|