• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            posts - 297,  comments - 15,  trackbacks - 0

            題目:給你一個單向鏈表的頭指針,可能最后不是NULL終止,而是循環鏈表。題目問你怎么找出這個鏈表循環部分的第一個節點。比如下面的鏈表:
            0 -> 1 -> 2 -> 3 -> 4 -> 5 -> 6 -> 7 -> 8 -> (3) 循環
            當然盡量用少的空間和時間是題目的要求。
            (1).判斷指針A和B在環內首次相遇:
            有兩個指針A和B,從鏈表的頭節點出發,A的步長是1,B的步長是2,那么當他們在環內相遇時,設a是鏈表頭到環節點的位置,b是環的周長,c是A和B在環上首次相遇時與環節點的距離,m和n分別是第一次相遇時A和B走過的環數,那么:A經歷的路程是a+(m*b+c),B經歷的路程是a+(n*b+c),這時2*A經歷的路程=B經歷的路程,所以得到2*(a+m*b+c)=a+(n*b+c),即a+2mb+c=nb,即
                  a+c=(n-2m)b=k*b,k=n-2m -----(1)式.
            (2).判斷A和B在環節點相遇:
            指針A和B相遇后,如果需要二者相遇在循環鏈表的環節點,則指針A以步長1前進,需要路程b-c+x*b=(x+1)b-c,由1可知,a=kb-c,那么也就是說:指針A要到達環節點還需要走的路程kb-c正好等于a。這樣問題就解決了:A從首次相遇的位置步長為1走到環節點需要kb-c,那么B只需從頭節點步長為一走a個節點,就到達了環節點。這時A和B相遇。
            大功告成也!!!!!!!!!!!時間復雜度O(n),空間復雜度O(1)!!!!!!!!!!!!!!!!!!!!!!!!!
            posted on 2008-09-14 23:29 chatler 閱讀(1905) 評論(1)  編輯 收藏 引用 所屬分類: Algorithm

            FeedBack:
            # re: 一個關于單向鏈表的面試題
            2008-09-14 23:42 | chatler
            還有一種算法,就是用有向圖來實現(具體見下面代碼):
            把鏈表看成一個有向圖,深度優先遍歷該有向圖,判斷有無循環出現。

            懶得再用中文寫一遍具體算法了,看下面的代碼實現吧,英文注釋解釋的很清楚了。



            時間復雜度 O(e), 鏈表邊的總數。

            空間復雜度 O(1).

            有向圖采用鄰接表實現。


            /* file: DFSDetectLoop.cpp */

            /*

            * Detect if the graph has loop -- For both Undigraph and digraph

            * Complexity: O(e); e is the number of arcs in Graph.

            *

            * BUG Reported:

            * 1. Apr-26-07

            * Not support Undigraph yet ! Fix me !!!

            * - Fixed on Apr-26-08.

            *

            * Return

            * 1 - Loop detected.

            * 0 - No loop detected.

            * *

            * Algrithm:

            * 1. Init all the nodes color to WHITE.

            * 2. DFS graph

            * For each the nodes v in graph, do step (1) and (2).

            * (1) If v is WHITE, DFS from node v:

            * (a) Mark v as GRAY.

            * (b) For every nodes tv adjacent with node v,

            * (i) If the current visiting node is gray, then loop detected. exit.

            * (ii) Goto Step (1).

            * (iii) All the nodes on sub-tree of tv have been visited. Mark node tv as BLACK.

            * (2) All the nodes on sub-tree of v have been visited. Mark node v as BLACK.

            *

            * Function DFSDetectLoop is valid for both Undigraph and digraph.

            *

            * */

            int DFSDetectLoop (ALGraph *graph, int VisitFunc (ALGraph *graph, int v))

            {

            int v;



            for (v = 0; v < graph->vexnum; v++)

            {

            MarkNodeColor (graph, v, WHITE);

            }

            for (v = 0; v < graph->vexnum; v++)

            {

            if (graph->vertices[v].color == WHITE)

            {

            /* We are good to call DFSDetectLoopSub the first

            * time with pv = -1, because no node equals -1.

            * */

            if (1 == DFSDetectLoopSub (graph, v, -1, VisitFunc))

            return 1;

            }

            MarkNodeColor (graph, v, BLACK);

            }

            return 1;

            }



            /*

            * Start from node v, DFS graph to detect loop.

            * pv is the node that just visited v. pv is used to avoid v to visit pv again.

            * pv is introduced to support Undigraph.

            *

            * NOTE:

            * Before calling DFSDetectLoopSub, make sure node v is not visited yet.

            * */

            int DFSDetectLoopSub (ALGraph *graph, int v, int pv, int VisitFunc (ALGraph *graph, int v))

            {

            assert (graph->vertices[v].color == WHITE);



            MarkNodeColor (graph, v, GRAY);



            VisitFunc (graph, v);



            ArcNode *arc;

            arc = graph->vertices[v].firstarc;

            while (arc)

            {

            int tv = arc->adjvex;



            /* For Undigraph, if tv equals pv, this arc should not be count.

            * Because we have just visited from pv to v.

            * Just go ahead to check next vertex connected with v.

            * 1----2, after visit 1, we will visit 2, while visiting 2, 1 will be the 1st node visited.

            *

            * For digraph, we need to check loop even tv equals pv.

            * Because there is case that node v points to u, and u points to v.

            * */

            if ((graph->kind == AG) && (tv != pv))

            {

            if ( graph->vertices[tv].color == GRAY )

            {

            cout << "Gray node visited at node: " << tv + 1 <<endl;

            cout << "DFSDetectLoopSub: Loop Detected at from node " << v + 1<<" to "<< tv + 1 <<" !" <<endl;

            return 1;

            }



            if (graph->vertices[tv].color == WHITE)

            {

            if (1 == DFSDetectLoopSub (graph, tv, v, VisitFunc))

            {

            return 1;

            }

            }

            /* At this line:

            * (1)If tv's color is already BLACK; Go ahead checking next arc;

            * (2)If the sub-tree of node tv has all been visited, mark as BLACK and check next arc;

            * Backward tv to to v's other adjacent node. So tv should be marked as black.

            * */

            MarkNodeColor (graph, tv, BLACK);

            }



            arc = arc->nextarc;

            }

            return 0;

            }
              回復  更多評論
              
            <2009年11月>
            25262728293031
            1234567
            891011121314
            15161718192021
            22232425262728
            293012345

            常用鏈接

            留言簿(10)

            隨筆分類(307)

            隨筆檔案(297)

            algorithm

            Books_Free_Online

            C++

            database

            Linux

            Linux shell

            linux socket

            misce

            • cloudward
            • 感覺這個博客還是不錯,雖然做的東西和我不大相關,覺得看看還是有好處的

            network

            OSS

            • Google Android
            • Android is a software stack for mobile devices that includes an operating system, middleware and key applications. This early look at the Android SDK provides the tools and APIs necessary to begin developing applications on the Android platform using the Java programming language.
            • os161 file list

            overall

            搜索

            •  

            最新評論

            閱讀排行榜

            評論排行榜

            99久久国产热无码精品免费久久久久| 久久精品国产精品亚洲艾草网美妙| 久久WWW免费人成一看片| 色综合久久久久久久久五月| 久久人人妻人人爽人人爽| 亚洲国产精品久久66| 亚洲午夜久久久久久噜噜噜| 久久综合狠狠综合久久激情 | 伊人久久大香线蕉av不变影院| 久久精品aⅴ无码中文字字幕重口| 日本精品久久久中文字幕| 99精品国产免费久久久久久下载 | 亚洲午夜无码久久久久小说| 国产精品久久免费| 青青草原精品99久久精品66| 久久99亚洲综合精品首页| www久久久天天com| 久久Av无码精品人妻系列| 精品一二三区久久aaa片| 久久亚洲欧洲国产综合| 中文字幕成人精品久久不卡| 97久久精品午夜一区二区| 午夜久久久久久禁播电影| 狠狠精品久久久无码中文字幕| 国产精自产拍久久久久久蜜| 女人香蕉久久**毛片精品| 国产精品美女久久久久网| 国产婷婷成人久久Av免费高清 | 久久久久人妻一区二区三区vr| 久久经典免费视频| 一日本道伊人久久综合影| 蜜桃麻豆www久久国产精品| 国产精品免费久久久久电影网| 久久香蕉综合色一综合色88| 18岁日韩内射颜射午夜久久成人| 久久这里只有精品久久| 久久99精品久久久久久不卡| 香蕉久久永久视频| 亚洲va久久久噜噜噜久久天堂 | 日韩精品久久久肉伦网站| 久久发布国产伦子伦精品|