求多邊形的核
/**//*************************************************************************
Author: WHU_GCC
Created Time: 2007-8-10 11:46:29
File Name: pku3335.cpp
Description:
************************************************************************/
#include <algorithm>
#include <iostream>
#include <sstream>
#include <string>
#include <queue>
#include <list>
#include <set>
#include <map>
#include <cmath>
#include <vector>
#include <cctype>
#include <cstring>
using namespace std;
#define out(x) (cout<<#x<<": "<<x<<endl)
const int maxint=0x7FFFFFFF;
const long long maxlonglong=0x7FFFFFFFFFFFFFFFLL;
template<class T>void show(T a, int n)
{for(int i=0; i<n; ++i) cout<<a[i]<<' '; cout<<endl;}
template<class T>void show(T a, int r, int l){for(int i=0; i<r; ++i)show(a[i],l);cout<<endl;}
#define EPS 1e-10
#define MaxN 3001
struct point
{
double x, y;
};
struct cp
{
int n;
point p[MaxN];
};
point intersectL(double a1, double b1, double c1, double a2, double b2, double c2)
{
point ret;
ret.y = (a1 * c2 - c1 * a2) / (b1 * a2 - a1 * b2);
if (fabs(a2) < EPS)
ret.x = -(b1 * ret.y + c1) / a1;
else
ret.x = -(b2 * ret.y + c2) / a2;
return ret;
}
bool isEqual(point inpA, point inpB)
{
return (fabs(inpA.x - inpB.x) < EPS && fabs(inpA.y - inpB.y) < EPS);
}
double Cross(point inpA, point inpB, point inpC)
{
return (inpB.x - inpA.x) * (inpC.y - inpA.y) - (inpC.x - inpA.x) * (inpB.y - inpA.y);
}
void Get_line(point inpA, point inpB, double &a1, double &b1, double &c1)
{
a1 = inpB.y - inpA.y;
b1 = inpA.x - inpB.x;
c1 = inpA.y * (inpB.x - inpA.x) - inpA.x * (inpB.y - inpA.y);
}
cp cut(point inpA, point inpB, cp incp)
{
cp ret;
point cross;
int i, j;
double t1, t2;
double a1, b1, c1, a2, b2, c2;
ret.n = 0;
for (i = 0; i < incp.n; i++)
{
j = i + 1;
t1 = Cross(inpA, inpB, incp.p[i]);
t2 = Cross(inpA, inpB, incp.p[j]);
if (t1 < EPS && t2 < EPS)
{
ret.p[ret.n++] = incp.p[i];
ret.p[ret.n++] = incp.p[j];
}
else if (t1 > EPS && t2 > EPS)
continue;
else
{
Get_line(inpA, inpB, a1, b1, c1);
Get_line(incp.p[i], incp.p[j], a2, b2, c2);
cross = intersectL(a1, b1, c1, a2, b2, c2);
if (t1 < EPS)
{
ret.p[ret.n++] = incp.p[i];
ret.p[ret.n++] = cross;
}
else
{
ret.p[ret.n++] = cross;
ret.p[ret.n++] = incp.p[j];
}
}
}
if (ret.n == 0) return ret;
for (i = 1, j = 1; i < ret.n; i++)
if (!isEqual(ret.p[i - 1], ret.p[i]))
ret.p[j++] = ret.p[i];
ret.n = j;
if (ret.n != 1 && isEqual(ret.p[ret.n - 1], ret.p[0])) ret.n--;
ret.p[ret.n] = ret.p[0];
return ret;
}
int main()
{
int ca;
int n;
cp input, ret;
for (scanf("%d", &ca); ca--;)
{
scanf("%d", &n);
input.n = n;
for (int i = 0; i < n; i++)
scanf("%lf%lf", &input.p[i].x, &input.p[i].y);
input.p[input.n] = input.p[0];
ret = input;
for (int i = 0; i < input.n; i++)
ret = cut(input.p[i], input.p[i + 1], ret);
if (ret.n >= 1) printf("YES\n");
else printf("NO\n");
}
return 0;
}