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            Exponentiation
            Time Limit: 500MS Memory Limit: 10000K
            Total Submissions: 68964 Accepted: 16146

            Description

            Problems involving the computation of exact values of very large magnitude and precision are common. For example, the computation of the national debt is a taxing experience for many computer systems. 

            This problem requires that you write a program to compute the exact value of Rn where R is a real number ( 0.0 < R < 99.999 ) and n is an integer such that 0 < n <= 25.

            Input

            The input will consist of a set of pairs of values for R and n. The R value will occupy columns 1 through 6, and the n value will be in columns 8 and 9.

            Output

            The output will consist of one line for each line of input giving the exact value of R^n. Leading zeros should be suppressed in the output. Insignificant trailing zeros must not be printed. Don't print the decimal point if the result is an integer.

            Sample Input

            95.123 12
            0.4321 20
            5.1234 15
            6.7592  9
            98.999 10
            1.0100 12
            

            Sample Output

            548815620517731830194541.899025343415715973535967221869852721
            .00000005148554641076956121994511276767154838481760200726351203835429763013462401
            43992025569.928573701266488041146654993318703707511666295476720493953024
            29448126.764121021618164430206909037173276672
            90429072743629540498.107596019456651774561044010001
            1.126825030131969720661201
            雖然效率低點兒,但代碼非常簡單,容易實現,真正比賽還是很好用的。。。
            import java.io.*;
            import java.util.*;
            import java.math.*;

            public class Main{
                public static void main( String args[] )
                {
                    BigDecimal num;
                    int n;
                    String r;
                    Scanner cin = new Scanner(System.in);
                    
                    while(cin.hasNextBigDecimal())
                    {
                        num = cin.nextBigDecimal();
                        n = cin.nextInt();
                        
                        num = num.pow(n);
                        r = num.stripTrailingZeros().toPlainString();//BigDecimal.toPlainString 避免輸出時產生科學計數法形式
                        if(r.startsWith("0."))
                            r = r.substring(1);
                        System.out.println(r);
                    }
                }
            }
            posted on 2010-05-26 07:30 Vontroy 閱讀(682) 評論(0)  編輯 收藏 引用 所屬分類: 大數/高精度POJ
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