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            二維循環數據,在實際中的應用!

            好久沒有在這里放文章了,今天灌點水,自己寫的小程序。

            #define frows 128
            #define fcols 128
            #define mrows 5
            #define mcols 5

            float fdem[frows][fcols];
            float mdem[mrows][mcols];

            #define PRINT_TEST????????\
            ?printf("\n\n --------mdem array---------");?\
            ?printf("\n frr=%d, fcc=%d", frr, fcc);??\
            ?printf("\n mrr=%d, mcc=%d", mrr, mcc);??\
            ?for(i=mrr; i<mrr+mrows; i++){????\
            ??int r = i % mrows;??????\
            ??printf("\n ");???????\
            ??for(j=mcc; j<mcc+mcols; j++){???\
            ???int c = j % mcols;?????\
            ???printf("%0.3f\t ", mdem[r][c]);??\
            ??}??????????\
            ?}??????????

            int main(int argc, char* argv[])
            {
            ?int i,j;
            ?int step=0;??//在mem中跳過的格子數
            ?int steplen=2;?//mem中一個格子對應在file跳過的格子數

            ?//初始化
            ?for(i=0; i<frows; i++){
            ??for(j=0; j<fcols; j++){
            ???fdem[i][j] = i + j*0.001f;
            ??}
            ?}

            ?int frr=0; int fcc=0; int mrr=0; int mcc=0;

            ?for(i=mrr; i<mrr+mrows; i++){
            ??int r = i % mrows;
            ??for(j=mcc; j<mcc+mcols; j++){
            ???int c = j % mcols;
            ???mdem[r][c] = fdem[frr + (i-mrr)*steplen][fcc+ (j-mcc)*steplen];??
            ??}
            ?}

            ?PRINT_TEST;

            ?//向右平移
            ?step=3;
            ?for(j=mcc; j<mcc+step; j++){
            ??int c = j % mcols;
            ??for(i=mrr; i<mrr+mrows; i++){
            ???int r = i % mrows;
            ???int rr = frr + (i-mrr) * steplen;
            ???int cc = fcc + (mcols + j-mcc) * steplen;
            ???mdem[r][c] = fdem[rr][cc];?
            ??}
            ?}
            ?fcc += step * steplen;
            ?mcc += step;
            ?PRINT_TEST;

            ?//向左平移
            ?step=3;
            ?for(j=mcc-1; j>=mcc-step; j--){
            ??int c = (j + mcols) % mcols;
            ??for(i=mrr; i<mrr+mrows; i++){
            ???int r = i % mrows;
            ???int rr = frr + (i-mrr) * steplen;
            ???int cc = fcc - (mcc-j) * steplen;
            ???mdem[r][c] = fdem[rr][cc];?
            ??}
            ?}
            ?fcc -= step * steplen;
            ?mcc -= step;
            ?PRINT_TEST;

            ?//向下平移
            ?step=3;
            ?for(i=mrr; i<mrr+step; i++){
            ??int r = i % mrows;
            ??for(j=mcc; j<mcc+mcols; j++){
            ???int c = j % mcols;
            ???int cc = fcc + (j-mcc) * steplen;
            ???int rr = frr + (mrows + i-mrr) * steplen;
            ???mdem[r][c] = fdem[rr][cc];?
            ??}
            ?}
            ?frr += step * steplen;
            ?mrr += step;
            ?PRINT_TEST;
            ?
            ?//向上平移
            ?step=3;
            ?for(i=mrr-1; i>=mrr-step; i--){
            ??int r = (i + mrows) % mrows;
            ??for(j=mcc; j<mcc+mcols; j++){
            ???int c = j % mcols;
            ???int cc = fcc + (j-mcc) * steplen;
            ???int rr = frr - (mrr-i) * steplen;
            ???mdem[r][c] = fdem[rr][cc];?
            ??}
            ?}
            ?frr -= step * steplen;
            ?mrr -= step;
            ?PRINT_TEST;

            ?return 0;
            }

            posted on 2006-05-20 21:58 zmj 閱讀(716) 評論(0)  編輯 收藏 引用

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