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            Why so serious? --[NKU]schindlerlee

            2010-06-11 00:40 spoj1182 ,dp, number theory, binary search 數(shù)位類統(tǒng)計(jì)問題

            詳見國家集訓(xùn)隊(duì)2009論文集 14.劉聰 <<淺談數(shù)位類統(tǒng)計(jì)問題>>
            這到題需要非常注意復(fù)數(shù)的操作,其實(shí)完全可以講負(fù)數(shù)轉(zhuǎn)化為整數(shù)操作
            也就是int轉(zhuǎn)換成unsigned int
            還有就是要注意,int型正數(shù),右移補(bǔ)0,負(fù)數(shù)右移是補(bǔ)1的,
            ??1?
            ??2?/*
            ??3??*?SOUR:spoj1182
            ??4??*?ALGO:dp,?number?theory,?binary?search
            ??5??*?DATE:?2010年?06月?08日?星期二?19:47:51?CST
            ??6??*?COMM:5
            ??7??*?*/
            ??8?#include<iostream>
            ??9?#include<cstdio>
            ?10?#include<cstdlib>
            ?11?#include<cstring>
            ?12?#include<algorithm>
            ?13?#include<queue>
            ?14?#include<vector>
            ?15?#include<map>
            ?16?using?namespace?std;
            ?17?#define?pb(x)?push_back(x)
            ?18?//#define?X?first
            ?19?//#define?Y?second
            ?20?typedef?vector?<?int?>vi;
            ?21?typedef?pair?<?int,?int?>pii;
            ?22?typedef?long?long?LL;
            ?23?typedef?unsigned?long?long?ULL;
            ?24?typedef?unsigned?int?uint;
            ?25?
            ?26?template?<class?T>?void?ckmin(T?&a,T?b)?{?if?(a?>?b)?{?a?=?b;?}?}
            ?27?template?<class?T>?void?ckmax(T?&a,T?b)?{?if?(a?<?b)?{?a?=?b;?}?}
            ?28?int?countbit(int?n)?{?return?n?==?0???0?:?1?+?countbit(n?&?(n?-?1));?}
            ?29?
            ?30?const?int?maxint?=?0x7fffffff;
            ?31?const?long?long?max64?=?0x7fffffffffffffffll;
            ?32?int?cnt[40][40],?sum[40];
            ?33?int?X,?Y,?K;
            ?34?
            ?35?void?pre()
            ?36??????//算出cnt[長(zhǎng)度][含多少個(gè)1]的方案數(shù)
            ?37?{
            ?38???int?i,j;
            ?39???cnt[0][0]?=?1;
            ?40???for?(i?=?1;i?<=?32;i++)?{
            ?41???????cnt[i][0]?=?cnt[i-1][0];
            ?42???????for?(j?=?1;j?<=?32;j++)?{
            ?43???????????cnt[i][j]?=?cnt[i-1][j]?+?cnt[i-1][j-1];
            ?44???????}
            ?45???}
            ?46?}
            ?47?
            ?48?int?num[40],?top;
            ?49?int?summ(uint?X,?int?R,?bool?flag?=?false)
            ?50?{
            ?51???memset(num,?0,?sizeof(num));
            ?52???top?=?1;
            ?53???while?(X)?{
            ?54???????num[top++]?=?X?&?1;
            ?55???????X?>>=?1;
            ?56???}
            ?57???if?(flag)?{
            ?58???????for?(int?i?=?1;i?<=?top;i++)?{
            ?59???????????if?(num[i]?==?0)?{
            ?60???????????????num[i]?=?1;
            ?61???????????????for?(int?j?=?i?-?1;j?>=?1;j--)?{
            ?62???????????????????num[j]?=?0;
            ?63???????????????}
            ?64???????????????if?(i?==?top)?{?top++;?}
            ?65???????????????break;
            ?66???????????}
            ?67???????}
            ?68???}
            ?69???int?ans?=?0,?one?=?0,?i;
            ?70???for?(i?=?top?-?1;i?>=?1;i--)?{
            ?71???????if?(R?>=?one?&&?num[i]?==?1)?{
            ?72???????????ans?+=?cnt[i?-?1][R?-?one];
            ?73???????????one++;
            ?74???????}
            ?75???}
            ?76???return?ans;
            ?77?}
            ?78?
            ?79?int?summarize(uint?X,?uint?Y,?int?digit)
            ?80??????//[X,?Y]?中1的個(gè)數(shù)為digit的?數(shù)字個(gè)數(shù)
            ?81?{?return?summ(Y,?digit,?1)?-?summ(X,?digit,?0);?}
            ?82?
            ?83?void?proc()
            ?84?{
            ?85???int?i,?j,?one?=?-1;
            ?86???memset(sum,?0,?sizeof(sum));
            ?87???for?(i?=?0;i?<?32;i++)?{
            ?88???????sum[i]?=?summarize(X,?Y,?i)?;
            ?89???????if?(K??>?sum[i])?{
            ?90???????????K?-=?sum[i];
            ?91???????}else?{
            ?92???????????one?=?i;
            ?93???????????break;
            ?94???????}
            ?95???}
            ?96???if?(Y?<?X)?{?swap(X,?Y);?}
            ?97???int?left?=?X,?right?=?Y;
            ?98???while?(left?<?right)?{?//binary?search?the?value?expected
            ?99???????int?mid?=?(left?+?right?+?1)?/?2;
            100???????if?(summarize(X,?mid,?one)?<=?K)?{
            101???????????left?=?mid;
            102???????}else?{
            103???????????right?=?mid?-?1;
            104???????}
            105???}
            106???while?(countbit(left)?!=?one)?{?left?--;?}?//?attention
            107?
            108???int?ans?=?0;
            109???for?(i?=?0;i?<?32;i++)?{
            110???????if?(left?&?(1?<<?i))?{
            111???????????ans?|=?1?<<?i;
            112???????}
            113???}
            114???printf("%d\n",?ans);
            115?}
            116?
            117?int?main()
            118?{
            119???int?i,?j,?testcase;
            120???pre();
            121???scanf("%d",?&testcase);
            122???while?(testcase--?)?{
            123???????scanf("%d?%d?%d",?&X,?&Y,?&K);
            124???????proc();
            125???}
            126???return?0;
            127?}
            128?

            posted on 2010-06-11 00:39 schindlerlee 閱讀(1575) 評(píng)論(0)  編輯 收藏 引用 所屬分類: 解題報(bào)告

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