• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            隨筆 - 87  文章 - 279  trackbacks - 0
            <2007年10月>
            30123456
            78910111213
            14151617181920
            21222324252627
            28293031123
            45678910

            潛心看書研究!

            常用鏈接

            留言簿(19)

            隨筆分類(81)

            文章分類(89)

            相冊

            ACM OJ

            My friends

            搜索

            •  

            積分與排名

            • 積分 - 218001
            • 排名 - 117

            最新評論

            閱讀排行榜

            評論排行榜

            Sailboat

            Problem H: Sailboat

            In the sailboat race, the contestant is requested to along with the prearrange path. Sailing ship's power comes from wind power and contestant's manpower. The wind power can completely used.

            In a competition, the contestants are requested to along with a 1/4 circles with radius R, the sailboat will goto east from south. During this process, the wind direction is straight from west to the east with constant speed and power.

            In order to maintain the travel direction, the athlete must adjust the sail to the vertical angle from movement direction in any time.

            If the speed of sailboat is proportional to the power at movement direction, the proportional factor is k. Supposes the wind power is f, the athlete manpower is h, please given the time of sailboat from the beginning to the end.

            Input

            The first line of each case consists of 4 double number, that is radius of path: R, wind power: f,athlete manpower: h and proportional factor:k. In order to avoid the floating point error, you needn't output the answer directly. The next line is a integer n, the following n lines gives a double value which is candidate answer.

            Output

            For each candidate of each case, Only "Yes" or "No" should be printed. Output "Yes" if the relative error to your answer is less than 3%, otherwise "No". For example, if the model answer is 100, and the candidate is 98 or 102, you should output "Yes". Output one blank line between neighboring case

            Sample Input

            1.0 2.0 1.0 1.0
            2
            0.35
            0.76
            

            Sample Output

            No
            Yes
            

            Problem Source: provided by skywind

            #include <iostream>
            #include 
            <cmath>
            using namespace std;

            const int MAXN = 100;
            const double PI = acos(-1.0);

            double R, F, H, K, ans;
            int n, cas;

            double func(double x) {
                
            return R / K / (H + F * cos(x));
            }


            double romberg(double a, double b, double EPS = 1e-6{
                
            double t[MAXN][MAXN] = {0}, tmp;
                
            int i, j, k, k2, m, m4;
                t[
            0][0= (func(a) + func(b)) * (b - a) / 2;
                k 
            = 1; k2 = 1;
                
            while (1{
                    tmp  
            = 0;
                    
            for (i = 1; i <= k2; i++{
                        tmp 
            += func(a + (2 * i - 1* (b - a) / (2 * k2));
                    }

                    t[
            0][k] = (t[0][k - 1+ tmp * (b - a) / k2) / 2;
                    
            for (m = 1, m4=4; m <= k; m++, m4 *= 4{
                        t[m][k 
            - m] = (m4 * t[m - 1][k - m + 1- t[m - 1][k - m]) / (m4 - 1);
                    }

                    
            if (fabs(t[k][0- t[k - 1][0]) < EPS) break;
                    k
            ++; k2 *= 2;
                }

                
            return t[k][0];
            }


            void solve() {
                
            double tmp;
                scanf(
            "%lf"&tmp);
                
            if (fabs(tmp - ans) / ans < 0.03) printf("Yes\n");
                
            else printf("No\n");
            }


            int main() {
                freopen(
            "2457.in""r", stdin);
                
            while (scanf("%lf%lf%lf%lf%d"&R, &F, &H, &K, &n) != EOF) {
                    
            if (cas) printf("\n");
                    
            else cas++;
                    ans 
            = romberg(0, PI/2);
                    
            while (n--{
                        solve();
                    }

                }

                
            return 0;
            }
            posted on 2007-10-20 01:02 閱讀(692) 評論(0)  編輯 收藏 引用 所屬分類: 算法&ACM
            狼狼综合久久久久综合网| 亚洲国产精品无码久久久秋霞2| 九九久久自然熟的香蕉图片| 精品久久久噜噜噜久久久| 久久国产一区二区| 日本亚洲色大成网站WWW久久| 精品久久久久久中文字幕大豆网 | 一本色道久久88综合日韩精品| 国产一区二区久久久| 麻豆亚洲AV永久无码精品久久| 91久久香蕉国产熟女线看| 久久久这里只有精品加勒比| 91久久精品国产91性色也| 大香伊人久久精品一区二区| 青青国产成人久久91网| 亚洲国产美女精品久久久久∴| 中文字幕亚洲综合久久| 久久久久人妻一区精品性色av| 精品久久久久久无码中文野结衣| 天天爽天天狠久久久综合麻豆| 欧美国产成人久久精品| 久久久久国产精品| 久久国产精品77777| 国产成人精品综合久久久久| 性做久久久久久久久久久| 久久久久国产精品| 久久精品无码一区二区三区| 亚洲AV无码久久精品成人| 无码人妻久久一区二区三区蜜桃 | 色综合久久88色综合天天| 亚洲精品乱码久久久久久自慰 | 亚洲人成网站999久久久综合| 国产视频久久| 国产精品久久久久乳精品爆| 99久久人人爽亚洲精品美女| 色综合久久综精品| 日本精品久久久久中文字幕8| 国产精品无码久久综合网| 天天综合久久久网| 久久国产成人| 久久成人国产精品免费软件|