給出一個0-1矩陣，輸出一個一樣大小的矩陣，其中每個元素代表原先矩陣對應(yīng)行和列的1的個數(shù)減去0的個數(shù)，O(n^2)直接做
1 #2482
2 #Runtime: 1162 ms (Beats 74.29%)
3 #Memory: 44.6 MB (Beats 80%)
4
5 class Solution(object):
6 def onesMinusZeros(self, grid):
7 """
8 :type grid: List[List[int]]
9 :rtype: List[List[int]]
10 """
11 n, m = len(grid), len(grid[0])
12 r = [0] * n
13 c = [0] * m
14 for i in xrange(n):
15 for j in xrange(m):
16 r[i] += grid[i][j]
17 c[j] += grid[i][j]
18 for i in xrange(n):
19 for j in xrange(m):
20 grid[i][j] = 2 * r[i] + 2 * c[j] - n - m
21 return grid