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            posts - 16,comments - 0,trackbacks - 0
            /*
            ????求行列式?O(n^3)
            */
            #?include?
            < string .h >

            int ?v[N][N],?t[N];

            int ?gcd( int ?a,? int ?b)?{ return ?b? ? ?gcd(b,?a % b):a;}

            int ?det( int ?n)
            {
            ????
            int ?c,?r,?i;
            ????
            int ?cof? = ? 1 ,?ret? = ? 1 ;
            ????
            int ?mc,?mh;
            ????
            ????
            for ?(c? = ? 1 ;?c? <= ?n;? ++ c)
            ????{
            ????????????
            for ?(r? = ?c;?r? <= ?n;? ++ r)
            ????????????{
            ????????????????????
            if ?(v[r][c]? < ? 0 )? for ?(i? = ?c;?i? <= ?n;? ++ i)?v[r][i]? = ? - v[r][i];
            ????????????????????????
            for ?(tt? = ? 0 ,?i? = ?c;?i? <= ?n;? ++ i)? if ?(v[r][i]? != ? 0 )
            ????????????????????????????????????
            if ?(tt? == ? 0 )?tt? = ?v[r][i];
            ????????????????????????????????????
            else ?tt?? = ?gcd(v[r][i],?tt);
            ????????????????????????
            if ?(tt? < ? 0 )?tt? = ? - tt;
            ????????????????????????
            if ?(tt? > ? 1 )? for ?(i? = ?c;?i? <= ?n;? ++ i)?v[r][i]? /= ?tt;
            ????????????????}
            ????????
            for ?(mv? = ?v[ 1 ][c],?mr = ?c,?r? = ?c + 1 ;?r? <= ?n;? ++ r)
            ????????{
            ????????????
            if ?(v[r][c]? < ? 0 )? for ?(ret? = ? - ret,?i? = ?c;?i? <= ?n;? ++ i)?v[r][i]? *= ? - 1 ;
            ????????????
            if ?(v[r][c]? > ?mv)?mv? = ?m[r][c],?mr? = ?r;
            ????????}
            ????????
            ????????
            /* ?行列式整列都為?0? */
            ????????
            if ?(mv? == ? 0 )? return ? 0 ;
            ????????
            ????????
            /* ?交換行使?v[c][c]?是?v[cn][c]?中最大的? */
            ????????memcpy(t
            + 1 ,?v[ 1 ] + 1 ,? sizeof (v[ 0 ][ 0 ]) * n);
            ????????memcpy(v[
            1 ] + 1 ,?v[mr] + 1 ,? sizeof (v[ 0 ][ 0 ]) * n);
            ????????memcpy(v[mr]
            + 1 ,?t + 1 ,? sizeof (v[ 0 ][ 0 ]) * n);
            ????????
            ????????
            /* ?消去?c+1..n?行行首非零元素? */
            ????????
            for ?(r? = ?c + 1 ;?r? <= ?n;? ++ r)? if ?(v[r][c])
            ????????{
            ????????????mh?
            = ?v[r][c] / gcd(mv,?v[r][c]));
            ????????????mc?
            = ?mv * mh / v[r][c];
            ????????????
            for ?(t? = ?c;?t? <= ?n;? ++ c)?????v[r][t]? = ?mc * v[r][t] - mh * v[c][t];
            ????????????cof?
            *= ?mc;
            ????????}
            ????????ret?
            *= ?v[c][c];
            ????}
            ????
            ????
            return ?ret * mc;
            }
            ?
            posted on 2012-08-30 17:20 yajunw 閱讀(374) 評論(0)  編輯 收藏 引用
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