模擬題，不說(shuō)了
1
#include <stdio.h>
2#include <string.h>
3
4char buf[5000];
5
6void Test()
7
{
8
int line = 0;
9 int len = strlen(buf);
10 int endLine = len/16;
11 int pos = 0;
12 for (int i = 0; i < endLine; ++i)
13
{
14 pos = i*16;
15 printf("%04x: ",pos);
16 for (int j = 0; j < 8; ++j)
17 {
18 printf("%x%x ",buf[pos+2*j],buf[pos+2*j+1]);
19
}
20 for (int j = 0; j < 16; ++j)
21 {
22 if (buf[pos+j] >= 'A' && buf[pos+j] <='Z')
23 {
24 printf("%c",buf[pos+j]-'A'+'a');
25 }
26 else if (buf[pos+j] >= 'a' && buf[pos+j] <='z')
27 {
28 printf("%c",buf[pos+j]-'a'+'A');
29 }
30 else
31 {
32 printf("%c",buf[pos+j]);
33 }
34 }
35 printf("\n");
36 }
37 pos = endLine*16;
38 if(pos < len)
39 {
40 printf("%04x: ",pos);
41 for (int j = 0; j < 16; ++j)
42 {
43 if(pos + j < len)
44 {
45 printf("%x",buf[pos+j]);
46
47 }
48 else
49 printf(" ");
50 if (j %2 == 1)
51 {
52 printf(" ");
53 }
54 }
55 for (int j = 0; j < 16; ++j)
56 {
57 if(pos + j < len)
58 {
59
60 if (buf[pos+j] >= 'A' && buf[pos+j] <='Z')
61 {
62 printf("%c",buf[pos+j]-'A'+'a');
63 }
64 else if (buf[pos+j] >= 'a' && buf[pos+j] <='z')
65 {
66 printf("%c",buf[pos+j]-'a'+'A');
67 }
68 else
69 {
70 printf("%c",buf[pos+j]);
71 }
72 }
73 }
74 printf("\n");
75 }
76
}
77
78int main()
79{
80 //freopen("data.txt","r",stdin);
81 //freopen("ans.txt","w",stdout);
82 while(gets(buf))
83 {
84 Test();
85 }
86} posted on 2012-03-26 10:42
bennycen 閱讀(1102)
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算法題解