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            posts - 71,  comments - 41,  trackbacks - 0

            MS面試曾出過(guò)這樣一道題目,將給定字符串按單詞翻轉(zhuǎn),如,"This is Charles" -> "Charles is This"

            方法一,需要額外緩沖區(qū)

            ?1 #include? < cstring >
            ?2 void ?ReverseByWords( char ? * s,? char ?seperator)
            ?3 {
            ?4 ???? int ?iRevTokenScanner? = ?strlen(s)? - ? 1 ;
            ?5 ???? char ? * buffer? = ? new ? char [iRevTokenScanner? + ? 2 ]();
            ?6 ???? int ?iWritePos? = ? 0 ;
            ?7 ???? int ?iWordEnd,?iWordReadPos;
            ?8
            ?9 ???? while ?(iRevTokenScanner? >= ? 0 )
            10 ???? {
            11 ???????? if ?(s[iRevTokenScanner]? != ?seperator)
            12 ???????? {
            13 ????????????iWordEnd? = ?iRevTokenScanner;
            14 ????????????
            15 ???????????? while ?(iRevTokenScanner? >= ? 0 ? && ??s[iRevTokenScanner]? != ?seperator)
            16 ????????????????iRevTokenScanner -- ;
            17 ????????????
            18 ????????????iWordReadPos? = ?iRevTokenScanner? + ? 1 ;
            19
            20 ???????????? while ?(iWordReadPos? <= ?iWordEnd)
            21 ????????????????buffer[iWritePos ++ ]? = ?s[iWordReadPos ++ ];
            22 ????????}

            23 ???????? else
            24 ???????? {
            25 ????????????buffer[iWritePos ++ ]? = ?s[iRevTokenScanner -- ];
            26 ????????}
            ?
            27 ????}

            28
            29 ????buffer[iWritePos]? = ? ' \0 ' ;
            30 ????strcpy(s,?buffer);
            31
            32 ???? if ?(buffer)
            33 ???? {
            34 ????????delete?[]?buffer;
            35 ????????buffer? = ? 0 ;
            36 ????}

            37 }

            方法二,個(gè)人比較prefer
            ?1void?ReverseString(char?*s,?int?start,?int?end)
            ?2{
            ?3????while?(start?<?end)
            ?4????{
            ?5????????if?(s[start]?!=?s[end])
            ?6????????{
            ?7????????????s[start]?^=?s[end];
            ?8????????????s[end]?^=?s[start];
            ?9????????????s[start]?^=?s[end];
            10????????}

            11????????????????
            12????????start++;
            13????????end--;
            14????}

            15}

            16
            17void?ReverseByWords(char?*s,?int?len,?char?seperator)
            18{
            19????int?start?=?0,?end?=?0;
            20
            21????ReverseString(s,?start,?len?-?1);
            22
            23????while?(end?<?len)
            24????{
            25????????if?(s[end]?!=?seperator)
            26????????{
            27????????????start?=?end;
            28
            29????????????while?(end?<?len?&&?s[end]?!=?seperator)
            30????????????????end++;
            31????????????end--;
            32
            33????????????ReverseString(s,?start,?end);
            34????????}

            35????????
            36????????end++;
            37
            38????}
            //while
            39}

            等有空再回來(lái)作注釋吧,現(xiàn)在挺忙的,先把code貼出來(lái)
            posted on 2006-11-16 18:50 Charles 閱讀(429) 評(píng)論(0)  編輯 收藏 引用 所屬分類: 面試小算法
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