|
日歷
| | 日 | 一 | 二 | 三 | 四 | 五 | 六 |
|---|
| 30 | 1 | 2 | 3 | 4 | 5 | 6 | | 7 | 8 | 9 | 10 | 11 | 12 | 13 | | 14 | 15 | 16 | 17 | 18 | 19 | 20 | | 21 | 22 | 23 | 24 | 25 | 26 | 27 | | 28 | 29 | 30 | 31 | 1 | 2 | 3 | | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|
統(tǒng)計
- 隨筆 - 30
- 文章 - 0
- 評論 - 51
- 引用 - 0
導(dǎo)航
常用鏈接
留言簿(4)
隨筆分類
隨筆檔案
ACM
搜索
最新評論
閱讀排行榜
評論排行榜
|
這道題我做的很郁悶，代碼也寫的不好、很長，方法也一般，有點麻煩，自己都覺得很爛，在提交的時候，發(fā)現(xiàn)別人的代碼寫的很簡練，但是不知道自己該怎么改進，希望大家多多提意見，謝謝大家了！
1 #include <string.h>
2#include <stdio.h>
3#define LENGTH 100
4
5typedef struct Number
6   {
7 int number;
8 int point;
9 int power;
10 }Number;
11
12void ConverTo(char *ch, int *real, int *p)
13{
14 int b = 1 ,sign = 1;
15 char *c = ch;
16 *real = 0;
17 *p = 0;
18 for( ; *c != '\0' && *c != '.'; c++)
19 *real = (*real)*10 + (*c - '0');
20 if( *c == '\0')
21  {
22 *p = 0;
23 }
24 else
25 {
26 *p = c-ch;
27 while( *(++c) != '\0')
28 *real = (*real)*10 + (*c - '0');
29 *p = c-ch-1- *p;
30 }
31}
32
33void Caculate(int *number, int real, int *p, int n, int size)
34{
35 int sum = 0;
36 int i ,t1, t2;
37 t1 = t2 = 0;
38 while( n-- > 0)
39 {
40 for(i = size-1; i >= 0; i--)
41 {
42 t1 = number[i]*real +t2;
43 number[i] = t1 % 10000;
44 t2 = t1 / 10000;
45 }
46 sum += *p;
47 }
48 *p = sum;
49}
50
51void Convert(char *ch, int *index, int *number, int *left, int right)
52{
53 int temp;
54
55 while(*left <= right)
56 {
57 temp = number[(*left)++];
58 ch[(*index)++] = temp/1000 + '0';
59 temp -= (temp/1000) * 1000;
60 ch[(*index)++] = temp/100 + '0';
61 temp -= (temp/100) * 100;
62 ch[(*index)++] = temp/10 + '0';
63 ch[(*index)++] = temp%10 + '0';
64
65 }
66}
67void ConverToChar(char *ch, int length,int *number, int left, int right, int point)
68{
69 int last,index, temp, p;
70 index = 0;
71 p = point/4;
72
73 Convert(ch, &index, number, &left, p-1);
74 temp = number[left++];
75 for(last = 0,p = 1000; last < 4; last++, p /= 10)
76 {
77 if( (4*(left-1) + last) == point)
78 ch[index++] = '.';
79 ch[index++] = temp/p + '0';
80 temp -= (temp/p) * p;
81 }
82 Convert(ch, &index, number, &left, right);
83}
84
85void Print(int *number, int p, int size)
86{
87 int left, right,index;
88 char ch[200];
89
90 index = (size*4-p)/4;
91 memset(ch, 0, sizeof(ch));
92
93 for(left = 0; left < index; left++)
94 {
95 if(number[left] == 0)
96 continue;
97 else
98 break;
99 }
100 for(right = size-1; right > index; right--)
101 {
102 if(number[right] == 0)
103 continue;
104 else
105 break;
106 }
107 ConverToChar(ch, sizeof(ch)-1, number, left, right, size*4-p);
108 for(left = 0; ch[left] == '0'; left++)
109 ;
110 for(right = sizeof(ch)-1; ch[right] == '\0' || ch[right] == '0'; right--)
111 ;
112 if(ch[right] == '.')
113 right--;
114 while(left <= right)
115 printf("%c", ch[left++]);
116 printf("\n");
117}
118
119int main(int argc, char* argv[])
120{
121
122 char ch[7];
123 Number n[LENGTH];
124 int i = 0, count = 0, p = 0;
125 int number[30];
126 memset(ch, 0, sizeof(ch));
127 while(scanf("%s %d", ch, &p) == 2)
128 {
129 ConverTo(ch, &n[count].number, &n[count].point);
130 n[count].power = p;
131 if(!(p<= 25 && p >0) || !(n[count].number> 0 && n[count].number < 99999))
132 {
133 break;
134 }
135 memset(ch,0, sizeof(ch));
136 count++;
137 }
138 while(i < count)
139 {
140 memset(number, 0, sizeof(number));
141 number[sizeof(number)/sizeof(int)-1] = 1;
142 Caculate(number, n[i].number, &n[i].point, n[i].power, sizeof(number)/sizeof(int));
143 Print(number,n[i].point,sizeof(number)/sizeof(int));
144 i++;
145 }
146 return 1;
147}
評論:
-
# re: 1001題探討
Posted @ 2008-06-16 12:33
能否把代碼的注釋寫下
代碼功能是做啥的！
如 打印一個3角等！ 回復(fù) 更多評論
|