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            心如止水
            Je n'ai pas le temps
            posts - 400,comments - 130,trackbacks - 0
            線段樹維護區間取反、區間覆蓋。
            拿日華哥哥的代碼對拍了好久終于AC啦。
            以下是我的代碼:
            /*
             * Author:  lee1r
             * Created Time:  2011/8/21 10:04:48
             * File Name: hdu3397.cpp
             
            */
            #include
            <iostream>
            #include
            <sstream>
            #include
            <fstream>
            #include
            <vector>
            #include
            <list>
            #include
            <deque>
            #include
            <queue>
            #include
            <stack>
            #include
            <map>
            #include
            <set>
            #include
            <bitset>
            #include
            <algorithm>
            #include
            <cstdio>
            #include
            <cstdlib>
            #include
            <cstring>
            #include
            <cctype>
            #include
            <cmath>
            #include
            <ctime>
            #define L(x) ((x)<<1)
            #define R(x) ((x)<<1|1)
            #define Half(x) ((x)>>1)
            #define Lowbit(x) ((x)&(-(x)))
            using namespace std;
            const int kInf(0x7f7f7f7f);
            const double kEps(1e-8);
            typedef unsigned 
            int uint;
            typedef 
            long long int64;
            typedef unsigned 
            long long uint64;

            int scanf(int &num)
            {
                
            char in;
                
            while((in=getchar())!=EOF && (in>'9' || in<'0'));
                
            if(in==EOF) return 0;
                num
            =in-'0';
                
            while(in=getchar(),in>='0' && in<='9') num*=10,num+=in-'0';
                
            return 1;
            }

            const int kMaxn(100007);

            struct Node
            {
                
            int a,b;
                
            int max0,lmax0,rmax0;
                
            int max1,lmax1,rmax1;
                
            int cnt0,cnt1;
                
            int cover,reverse;
            };

            int N,M;
            bool r[kMaxn];
            Node tree[kMaxn
            <<2];

            void PushDown(int node)
            {
                
            if(tree[node].cover!=-1)
                {
                    tree[L(node)].reverse
            =tree[R(node)].reverse=0;
                    tree[L(node)].cover
            =tree[R(node)].cover=tree[node].cover;
                    
            if(tree[node].cover==0)
                    {
                        tree[L(node)].cnt0
            =tree[L(node)].max0=tree[L(node)].lmax0=tree[L(node)].rmax0=(tree[L(node)].b-tree[L(node)].a+1);
                        tree[L(node)].cnt1
            =tree[L(node)].max1=tree[L(node)].lmax1=tree[L(node)].rmax1=0;
                        tree[R(node)].cnt0
            =tree[R(node)].max0=tree[R(node)].lmax0=tree[R(node)].rmax0=(tree[R(node)].b-tree[R(node)].a+1);
                        tree[R(node)].cnt1
            =tree[R(node)].max1=tree[R(node)].lmax1=tree[R(node)].rmax1=0;
                    }
                    
            else
                    {
                        tree[L(node)].cnt0
            =tree[L(node)].max0=tree[L(node)].lmax0=tree[L(node)].rmax0=0;
                        tree[L(node)].cnt1
            =tree[L(node)].max1=tree[L(node)].lmax1=tree[L(node)].rmax1=(tree[L(node)].b-tree[L(node)].a+1);
                        tree[R(node)].cnt0
            =tree[R(node)].max0=tree[R(node)].lmax0=tree[R(node)].rmax0=0;
                        tree[R(node)].cnt1
            =tree[R(node)].max1=tree[R(node)].lmax1=tree[R(node)].rmax1=(tree[R(node)].b-tree[R(node)].a+1);
                    }
                    tree[node].cover
            =-1;
                }
                
            if(tree[node].reverse)
                {
                    tree[node].reverse
            =0;
                    swap(tree[L(node)].max0,tree[L(node)].max1);
                    swap(tree[L(node)].lmax0,tree[L(node)].lmax1);
                    swap(tree[L(node)].rmax0,tree[L(node)].rmax1);
                    swap(tree[L(node)].cnt0,tree[L(node)].cnt1);
                    swap(tree[R(node)].max0,tree[R(node)].max1);
                    swap(tree[R(node)].lmax0,tree[R(node)].lmax1);
                    swap(tree[R(node)].rmax0,tree[R(node)].rmax1);
                    swap(tree[R(node)].cnt0,tree[R(node)].cnt1);
                    
                    tree[L(node)].reverse
            =!tree[L(node)].reverse;
                    tree[R(node)].reverse
            =!tree[R(node)].reverse;
                }
            }

            void PushUp(int node)
            {
                tree[node].max0
            =max(tree[L(node)].max0,tree[R(node)].max0);
                tree[node].max0
            =max(tree[node].max0,tree[L(node)].rmax0+tree[R(node)].lmax0);
                
            if(tree[L(node)].lmax0==tree[L(node)].b-tree[L(node)].a+1)
                    tree[node].lmax0
            =tree[L(node)].lmax0+tree[R(node)].lmax0;
                
            else
                    tree[node].lmax0
            =tree[L(node)].lmax0;
                
            if(tree[R(node)].rmax0==tree[R(node)].b-tree[R(node)].a+1)
                    tree[node].rmax0
            =tree[R(node)].rmax0+tree[L(node)].rmax0;
                
            else
                    tree[node].rmax0
            =tree[R(node)].rmax0;
                
                tree[node].max1
            =max(tree[L(node)].max1,tree[R(node)].max1);
                tree[node].max1
            =max(tree[node].max1,tree[L(node)].rmax1+tree[R(node)].lmax1);
                
            if(tree[L(node)].lmax1==tree[L(node)].b-tree[L(node)].a+1)
                    tree[node].lmax1
            =tree[L(node)].lmax1+tree[R(node)].lmax1;
                
            else
                    tree[node].lmax1
            =tree[L(node)].lmax1;
                
            if(tree[R(node)].rmax1==tree[R(node)].b-tree[R(node)].a+1)
                    tree[node].rmax1
            =tree[R(node)].rmax1+tree[L(node)].rmax1;
                
            else
                    tree[node].rmax1
            =tree[R(node)].rmax1;
                
                tree[node].cnt0
            =tree[L(node)].cnt0+tree[R(node)].cnt0;
                tree[node].cnt1
            =tree[L(node)].cnt1+tree[R(node)].cnt1;
            }

            void Build(int node,int x,int y)
            {
                tree[node].a
            =x;
                tree[node].b
            =y;
                tree[node].cover
            =-1;
                tree[node].reverse
            =0;
                
            if(x==y)
                {
                    tree[node].cnt0
            =tree[node].max0=tree[node].lmax0=tree[node].rmax0=!r[x];
                    tree[node].cnt1
            =tree[node].max1=tree[node].lmax1=tree[node].rmax1=r[x];
                }
                
            else
                {
                    
            int m(Half(x+y));
                    Build(L(node),x,m);
                    Build(R(node),m
            +1,y);
                    PushUp(node);
                }
            }

            void Modify(int node,int x,int y,int type)
            {
                
            if(x<=tree[node].a && tree[node].b<=y)
                {
                    
            if(type==0)
                    {
                        tree[node].reverse
            =0;
                        tree[node].cover
            =0;
                        tree[node].cnt0
            =tree[node].max0=tree[node].lmax0=tree[node].rmax0=tree[node].b-tree[node].a+1;
                        tree[node].cnt1
            =tree[node].max1=tree[node].lmax1=tree[node].rmax1=0;
                    }
                    
            else if(type==1)
                    {
                        tree[node].reverse
            =0;
                        tree[node].cover
            =1;
                        tree[node].cnt0
            =tree[node].max0=tree[node].lmax0=tree[node].rmax0=0;
                        tree[node].cnt1
            =tree[node].max1=tree[node].lmax1=tree[node].rmax1=tree[node].b-tree[node].a+1;
                    }
                    
            else if(type==2)
                    {
                        tree[node].reverse
            =!tree[node].reverse;
                        swap(tree[node].cnt0,tree[node].cnt1);
                        swap(tree[node].max0,tree[node].max1);
                        swap(tree[node].lmax0,tree[node].lmax1);
                        swap(tree[node].rmax0,tree[node].rmax1);
                    }
                }
                
            else
                {
                    PushDown(node);
                    
            int m(Half(tree[node].a+tree[node].b));
                    
            if(m>=x)
                        Modify(L(node),x,y,type);
                    
            if(m<y)
                        Modify(R(node),x,y,type);
                    PushUp(node);
                }
            }

            int Query1(int node,int x,int y)
            {
                
            if(x<=tree[node].a && tree[node].b<=y)
                    
            return tree[node].cnt1;
                PushDown(node);
                
            int m(Half(tree[node].a+tree[node].b)),re(0);
                
            if(m>=x)
                    re
            +=Query1(L(node),x,y);
                
            if(m<y)
                    re
            +=Query1(R(node),x,y);
                
            return re;
            }

            int Query2(int node,int x,int y)
            {
                
            if(x<=tree[node].a && tree[node].b<=y)
                    
            return tree[node].max1;
                PushDown(node);
                
            int m(Half(tree[node].a+tree[node].b));
                
            if(m>=y)
                    
            return Query2(L(node),x,y);
                
            if(m<x)
                    
            return Query2(R(node),x,y);
                
            return max(max(Query2(L(node),x,m),Query2(R(node),m+1,y)),min(tree[L(node)].rmax1,m-x+1)+min(tree[R(node)].lmax1,y-m));
            }

            int main()
            {
                
            int T;
                scanf(T);
                
            while(T--)
                {
                    scanf(N);
                    scanf(M);
                    
            for(int i=1;i<=N;i++)
                    {
                        
            int t;
                        scanf(t);
                        
            if(t)
                            r[i]
            =true;
                        
            else
                            r[i]
            =false;
                    }
                    
            //  Input
                    
                    Build(
            1,1,N);
                    
            //  Build
                    
                    
            while(M--)
                    {
                        
            int c,a,b;
                        scanf(c);
                        scanf(a);
                        scanf(b);
                        a
            ++;b++;
                        
            if(c<=2)
                            Modify(
            1,a,b,c);
                        
            else if(c==3)
                            printf(
            "%d\n",Query1(1,a,b));
                        
            else
                            printf(
            "%d\n",Query2(1,a,b));
                    }
                }
                
                
            return 0;
            }
            posted on 2011-08-22 18:57 lee1r 閱讀(476) 評論(2)  編輯 收藏 引用 所屬分類: 題目分類:數據結構

            FeedBack:
            # re: HDU 3397 Sequence operation[未登錄]
            2011-08-22 19:02 | Starry
            好飄逸的代碼~  回復  更多評論
              
            # re: HDU 3397 Sequence operation
            2011-08-22 19:05 | snowye
            DBL  回復  更多評論
              
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