這樣也可以：
#include <iostream>
using namespace std;

int main()
{
int Number1 = 23;
int Number2 = 33;

cout<<Number1<<"\n"<<Number2<<endl;

Number1 = Number1 + Number2;
Number2 = Number1 - Number2;
Number1 = Number1 - Number2;

cout<<Number1<<"\n"<<Number2<<endl;

return 0;
}

當然樓主的更猛，不會產生溢出，我這個方法可能產生溢出，呵呵_^_  回復  更多評論