In arithmetic we often use the scheme called 'round up by five' to round up a decimal fraction number into a decimal integer number whose fraction part equals to or is bigger than 0.5, otherwise, its fraction part is discarded.
In this problem, you are to implement a similar sheme called 'round up by six'.
Input
The first line of the input is an integer N indicating the number of cases you are to process. Then from the second line there are N lines, each containing a number (may or may not be fractional).
Output
For each number in the input, you are to print the round-up-by-six version of the number in a single line.
Sample Input
2
25.599
0.6

Sample Output
25
1

#include<iostream>
#include<cmath>
using namespace std;
int main()
{int n;
cin>>n;
while(n--)
{  double a;
cin>>a;
double b=floor(a);
if(a-b>=0.6)
cout<<b+1<<endl;
else
cout<<b<<endl;
}
return 0;
}