• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>

            poj3087

            Shuffle'm Up

            Time Limit: 1000MS Memory Limit: 65536K
            Total Submissions: 3434 Accepted: 1602

            Description

            A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of poker chips, S1 and S2, each stack containing C chips. Each stack may contain chips of several different colors.

            The actual shuffle operation is performed by interleaving a chip from S1 with a chip from S2 as shown below for C = 5:

            The single resultant stack, S12, contains 2 * C chips. The bottommost chip of S12 is the bottommost chip from S2. On top of that chip, is the bottommost chip from S1. The interleaving process continues taking the 2nd chip from the bottom of S2 and placing that on S12, followed by the 2nd chip from the bottom of S1 and so on until the topmost chip from S1 is placed on top of S12.

            After the shuffle operation, S12 is split into 2 new stacks by taking the bottommost C chips from S12 to form a new S1 and the topmost C chips from S12 to form a new S2. The shuffle operation may then be repeated to form a new S12.

            For this problem, you will write a program to determine if a particular resultant stack S12 can be formed by shuffling two stacks some number of times.

            Input

            The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.

            Each dataset consists of four lines of input. The first line of a dataset specifies an integer C, (1 ≤ C ≤ 100) which is the number of chips in each initial stack (S1 and S2). The second line of each dataset specifies the colors of each of the C chips in stack S1, starting with the bottommost chip. The third line of each dataset specifies the colors of each of the C chips in stack S2 starting with the bottommost chip. Colors are expressed as a single uppercase letter (A through H). There are no blanks or separators between the chip colors. The fourth line of each dataset contains 2 * C uppercase letters (A through H), representing the colors of the desired result of the shuffling of S1 and S2 zero or more times. The bottommost chip’s color is specified first.

            Output

            Output for each dataset consists of a single line that displays the dataset number (1 though N), a space, and an integer value which is the minimum number of shuffle operations required to get the desired resultant stack. If the desired result can not be reached using the input for the dataset, display the value negative 1 (−1) for the number of shuffle operations.

            Sample Input

            2
            4
            AHAH
            HAHA
            HHAAAAHH
            3
            CDE
            CDE
            EEDDCC

            Sample Output

            1 2
            2 -1
            題意就是兩坨牌,洗牌,看能不能到達所求的牌的狀態,如果能到達,最少幾步
            但是這題有個規定是,洗牌的規則是唯一的,所以完全可以用模擬來做
            我們可以把牌插起來,然后再平分成兩半,然后再插,直到能到達所求狀態或者出現了重復狀態
            或者從目標狀態出發找原來的狀態,同上
            在判重的時候不必記錄已經走過的狀態,只要記錄走第一步后的狀態,如果狀態和第一步后的狀態一樣的話,說明不能得到解
             1#include<stdio.h>
             2#include<string.h>
             3#include<math.h>
             4char s1[105],s2[150],s3[300],tmp[300],case1[150],case2[150];
             5char str1[150],str2[150];
             6int c;
             7int getans()
             8{
             9    int num,len,i;
            10    len=c*2;
            11    num=0;
            12    strcpy(tmp,s3);
            13    while(1)
            14    {
            15        for(i=0; i<len; i++)
            16            if(i%2==0)
            17            {
            18                str2[i/2]=tmp[i];
            19            }

            20            else if(i%2==1)
            21            {
            22                str1[i/2]=tmp[i];
            23            }

            24        str1[c]='\0';
            25        str2[c]='\0';
            26        if(num==0)
            27        {
            28            strcpy(case1,str1);
            29            strcpy(case2,str2);
            30        }

            31        num++;
            32        /*printf("%s\n",str1);
            33        printf("%s\n",str2);
            34        system("pause");*/

            35        if((strcmp(str1,s1)==0&&strcmp(str2,s2)==0))
            36            return num;
            37        else if(num!=1&&(strcmp(case1,str1)==0&&strcmp(case2,str2)==0))
            38        {
            39            return -1;
            40        }

            41        for(i=0; i<c; i++)
            42        {
            43            tmp[i]=str1[i];
            44        }

            45        for(i=c; i<len; i++)
            46        {
            47            tmp[i]=str2[i-c];
            48        }

            49        tmp[len]='\0';
            50    }

            51    /*if((strcmp(str1,s1)==0&&strcmp(str2,s2)==0))
            52        return num;
            53    else return -1;*/

            54}

            55int main()
            56{
            57    int t,i;
            58    scanf("%d",&t);
            59    for(i=1; i<=t; i++)
            60    {
            61        scanf("%d",&c);
            62        scanf("%s",&s1);
            63        scanf("%s",&s2);
            64        scanf("%s",&s3);
            65        printf("%d %d\n",i,getans());
            66    }

            67    return 0;
            68}

            69
            70/*
            71!(strcmp(str1,s1)==0&&strcmp(str2,s2)==0)
            72*/

            73

            posted on 2012-03-15 20:58 jh818012 閱讀(169) 評論(0)  編輯 收藏 引用

            <2025年7月>
            293012345
            6789101112
            13141516171819
            20212223242526
            272829303112
            3456789

            導航

            統計

            常用鏈接

            留言簿

            文章檔案(85)

            搜索

            最新評論

            • 1.?re: poj1426
            • 我嚓,,輝哥,,居然搜到你的題解了
            • --season
            • 2.?re: poj3083
            • @王私江
              (8+i)&3 相當于是 取余3的意思 因為 3 的 二進制是 000011 和(8+i)
            • --游客
            • 3.?re: poj3414[未登錄]
            • @王私江
              0ms
            • --jh818012
            • 4.?re: poj3414
            • 200+行,跑了多少ms呢?我的130+行哦,你菜啦,哈哈。
            • --王私江
            • 5.?re: poj1426
            • 評論內容較長,點擊標題查看
            • --王私江
            国产精品美女久久久m| 国产ww久久久久久久久久| 久久99精品久久久久久野外| 99久久精品无码一区二区毛片| 99久久精品无码一区二区毛片| 久久中文娱乐网| 久久久久亚洲AV无码网站| 久久国产热这里只有精品| 久久精品无码专区免费青青 | 一本大道久久a久久精品综合| 91精品国产91久久久久久蜜臀| 欧美激情精品久久久久久久| 国产精品久久久久久| 97精品伊人久久久大香线蕉| 久久九九青青国产精品| 婷婷久久综合| 久久婷婷成人综合色综合| 亚洲欧美国产精品专区久久| 99热都是精品久久久久久| 久久精品极品盛宴观看| 热RE99久久精品国产66热| 色偷偷88888欧美精品久久久| 精品99久久aaa一级毛片| 国产成人精品综合久久久久| 国产毛片久久久久久国产毛片| 国产69精品久久久久9999APGF | 色妞色综合久久夜夜| 久久国产精品二国产精品| 久久九九精品99国产精品| 久久天天躁狠狠躁夜夜不卡| 久久精品九九亚洲精品天堂| 色婷婷综合久久久久中文一区二区 | 99精品久久精品一区二区| 亚洲精品国产综合久久一线| 国内精品久久久久久久涩爱| 久久Av无码精品人妻系列| 精品无码久久久久国产动漫3d | 久久婷婷五月综合97色| 亚洲色大成网站www久久九| 久久精品国产精品亚洲精品| 久久久高清免费视频|