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POJ 2402- A Star not a Tree?(費馬點)

#include <cstdio>
2

#include <cmath>
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const int SIZE = 102;
5

struct TPoint
7

{
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double x ;
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double y ;
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} ;
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TPoint point[SIZE];
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int N;
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double Distance( const TPoint& p1, const TPoint& p2 )
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{
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return sqrt((p1.x - p2.x) * (p1.x - p2.x) + (p1.y - p2.y) * (p1.y - p2.y)) ;
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}
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double GetALLDist( const TPoint& p, const int& n )
21

{
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int i;
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double sum = 0.0;
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for ( i = 0; i < n; ++i )
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sum += Distance( p, point[i] );
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return sum;
29

}
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double GetFermatPoint( const int& n )
32

{
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TPoint st = point[0];
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TPoint tmp, nt;
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double t, step = 100, fermat = GetALLDist(st, n);
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while ( step > 0.2 )
38

{
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int ok = 1;
40

while ( ok ) {
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ok = 0;
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nt = st;
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tmp.x = st.x, tmp.y = st.y + step;
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t = GetALLDist(tmp, n);
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if ( t < fermat )
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{
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fermat = t;
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ok = 1;
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nt = tmp;
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}
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tmp.x = st.x, tmp.y = st.y - step;
57

t = GetALLDist(tmp, n);
59

if ( t < fermat )
60

{
61

fermat = t;
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ok = 1;
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nt = tmp;
64

}
65

tmp.x = st.x + step, tmp.y = st.y;
67

t = GetALLDist(tmp, n);
69

if ( t < fermat )
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{
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fermat = t;
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ok = 1;
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nt = tmp;
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}
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tmp.x = st.x - step, tmp.y = st.y;
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t = GetALLDist(tmp, n);
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if ( t < fermat )
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{
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fermat = t;
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ok = 1;
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nt = tmp;
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}
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st = nt;
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}
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step /= 2.0;
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}
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return fermat;
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}
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int main()
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{
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int i, ans;
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double t;
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scanf("%d", &N);
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for ( i = 0; i < N; ++i )
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{
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scanf("%lf %lf", &point[i].x, &point[i].y);
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}
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t = GetFermatPoint( N );
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ans = (int)(t + 0.5) * 100 / 100;
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112

printf("%d\n", ans);
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return 0;
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}

posted on 2009-03-31 12:08 巫閱讀(286) 評論(0) 編輯收藏引用所屬分類: 幾何

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