#include<stdio.h>
long f(__int64 n)
{
while(n!=0){
if(n%10==7)return 1;
n/=10;
}
return 0;
}
int main()
{
static __int64 a[1000000],n,m,i,j=0,f1;
for(i=7;i<1000000000;i++){
if(f(i)||i%7==0)
a[j]++;
else {
f1=1;
for(int k=0;k<j;k++)
if(a[j]<=a[k])f1=0;
if(f1){printf("p=%I64d,x=%I64d\n",a[j],i-a[j]);
j++;}
else a[j]=0;
}
}
}
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=3318比賽時(shí)沒有想到，就是靠人腦舉例，導(dǎo)致考慮不完整，出現(xiàn)很多錯(cuò)誤！后來經(jīng)高人指點(diǎn)，編學(xué)了個(gè)輔助程序，終于ac了！
O(∩_∩)O~，看來還是要好好利用電腦！！
主程序：
#include<stdio.h>
int main()
{
long n,t;
scanf("%d",&t);
while(t--){
scanf("%d",&n);
if(n==1)printf("7\n");
else if(n==2)printf("27\n");
else if(n<=10)printf("70\n");
else if(n<=11)printf("270\n");
else if(n<=100)printf("700\n");
else if(n<=101)printf("2700\n");
else if(n<=1000)printf("7000\n");
else if(n<=1002)printf("26999\n");
else if(n<=10000)printf("70000\n");
else if(n<=10001)printf("270000\n");
else if(n<=100000)printf("700000\n");
else if(n<=100001)printf("1699999\n");
else if(n<=1000000)printf("7000000\n");
else if(n<=1000001)printf("27000000\n");
else if(n<=10000000)printf("70000000\n");
else if(n<=10000001)printf("270000000\n");
else printf("700000000\n");
}
}
posted on 2009-05-04 22:14
zhoubaozhong 閱讀(447)
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