計(jì)算出1/1 + 2/1 + 3/2 + 5/3 + 8/5 + 13/8 + .....一直到第n項(xiàng)的和,
每項(xiàng)的分子分母是由斐波那契數(shù)列中取相鄰的兩個(gè)得到,計(jì)算結(jié)果保留三位小數(shù)
#include <iostream>
#include <iomanip>
using namespace std;

int main(){
int n;
double t;

while(cin>>n){
double a=1;
double b=1;
double sum=0;

for(int i=1;i<=n;i++){
sum+=a/b;
t=a;
a+=b;
b=t;
}cout<<setiosflags(ios::fixed)<<setprecision(3);
cout<<sum<<endl;
}
return 0;
}
每項(xiàng)的分子分母是由斐波那契數(shù)列中取相鄰的兩個(gè)得到,計(jì)算結(jié)果保留三位小數(shù)

























