• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            posts - 74,  comments - 33,  trackbacks - 0

            TimeLimit : 1 Second ? Memorylimit : 32 Megabyte ?

            Totalsubmit : 590 ? Accepted : 131

            Anti-terrorism is becoming more and more serious nowadays. The country now has n soldiers,and every solider has a score.

            We want to choose some soldiers to fulfill an urgent task. The soldiers chosen must be adjacent to each other in order to make sure that they can cooperate well. And all the soldiers chosen must have an average score greater than a.

            Now, please calculate how many ways can the chief of staff choose the soldiers.

            Input

            The first line consists of a single integer t, indicating number of test cases.

            For each test case, the first line gives n, the number of soldiers, and a, the minimum possible average score(n<=100000,a<=10000). The second line gives n integers, corresponding to the soldiers' scores in order. All the scores are no greater than 10000.

            Output

            An integer n, number of ways to choose the soldiers.

            Sample Input

            2
            5 3
            1 3 7 2 4
            1 1000
            9999

            Sample Output

            10
            1
            一個(gè)簡(jiǎn)稱(chēng)CS的題目其實(shí)找到規(guī)律的話就很簡(jiǎn)單了,一個(gè)Mergersort就能AC;
            Mergersort代碼如下:
            void?Mergersort(INT?l,INT?r){
            ????INT?i,j,sign;
            ????
            if(l>=r)return?;
            ????INT?mid
            =(l+r)>>1;
            ????Mergersort(l,mid);
            ????Mergersort(mid
            +1,r);
            ????sign
            =l,i=l,j=mid+1;
            ????
            while(i<=mid&&j<=r){
            ????????
            if(score[j]>score[i]){
            ????????????all
            +=mid-i+1;
            ????????????now[sign
            ++]=score[j++];????
            ????????}

            ????????
            else?now[sign++]=score[i++];????????
            ????}

            ????
            while(i<=mid)now[sign++]=score[i++];
            ????
            while(j<=r)now[sign++]=score[j++];
            ????
            for(i=l;i<=r;i++)
            ????????score[i]
            =now[i];
            ????
            return?;
            }
            posted on 2009-02-21 20:13 KNIGHT 閱讀(172) 評(píng)論(0)  編輯 收藏 引用

            只有注冊(cè)用戶登錄后才能發(fā)表評(píng)論。
            網(wǎng)站導(dǎo)航: 博客園   IT新聞   BlogJava   博問(wèn)   Chat2DB   管理


            <2009年1月>
            28293031123
            45678910
            11121314151617
            18192021222324
            25262728293031
            1234567

            常用鏈接

            留言簿(8)

            隨筆檔案

            文章檔案

            Friends

            OJ

            搜索

            •  

            最新評(píng)論

            閱讀排行榜

            評(píng)論排行榜

            国产福利电影一区二区三区,免费久久久久久久精 | 亚洲欧洲精品成人久久曰影片| 久久久久久亚洲精品不卡| 亚洲中文字幕无码久久2017| 国产精品久久久久久久久鸭| 好属妞这里只有精品久久| 国产91久久综合| 99久久国产精品免费一区二区| 精品熟女少妇av免费久久| 久久99精品久久久久久秒播| 亚洲精品无码久久毛片| 国内精品伊人久久久久av一坑| 久久精品国产72国产精福利| 精品免费久久久久久久| 中文字幕亚洲综合久久菠萝蜜| 国产精品久久久久久搜索| 亚洲中文字幕无码一久久区| 国产福利电影一区二区三区久久老子无码午夜伦不 | 无码伊人66久久大杳蕉网站谷歌| 国产午夜精品理论片久久| 蜜臀久久99精品久久久久久小说| 久久精品国产99久久久香蕉| 精品国际久久久久999波多野| 欧美国产成人久久精品| 久久精品中文字幕一区| 一本伊大人香蕉久久网手机| 精品久久一区二区| 91精品国产综合久久婷婷| 久久精品国产亚洲77777| 国产亚洲精久久久久久无码77777 国产亚洲精品久久久久秋霞 | 77777亚洲午夜久久多喷| 中文字幕无码久久精品青草| 久久亚洲电影| 一本久久a久久精品综合香蕉| 久久久精品视频免费观看| 久久精品一区二区影院| 开心久久婷婷综合中文字幕| 久久精品综合一区二区三区| 亚洲天堂久久久| 少妇久久久久久被弄高潮| 99久久久国产精品免费无卡顿|