• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            posts - 74,  comments - 33,  trackbacks - 0
            Balance
            Time Limit: 1000MS Memory Limit: 30000K
            Total Submissions: 1159 Accepted: 553

            Description

            Gigel has a strange "balance" and he wants to poise it. Actually, the device is different from any other ordinary balance.
            It orders two arms of negligible weight and each arm's length is 15. Some hooks are attached to these arms and Gigel wants to hang up some weights from his collection of G weights (1 <= G <= 20) knowing that these weights have distinct values in the range 1..25. Gigel may droop any weight of any hook but he is forced to use all the weights.
            Finally, Gigel managed to balance the device using the experience he gained at the National Olympiad in Informatics. Now he would like to know in how many ways the device can be balanced.

            Knowing the repartition of the hooks and the set of the weights write a program that calculates the number of possibilities to balance the device.
            It is guaranteed that will exist at least one solution for each test case at the evaluation.

            Input

            The input has the following structure:
            ? the first line contains the number C (2 <= C <= 20) and the number G (2 <= G <= 20);
            ? the next line contains C integer numbers (these numbers are also distinct and sorted in ascending order) in the range -15..15 representing the repartition of the hooks; each number represents the position relative to the center of the balance on the X axis (when no weights are attached the device is balanced and lined up to the X axis; the absolute value of the distances represents the distance between the hook and the balance center and the sign of the numbers determines the arm of the balance to which the hook is attached: '-' for the left arm and '+' for the right arm);
            ? on the next line there are G natural, distinct and sorted in ascending order numbers in the range 1..25 representing the weights' values.

            Output

            The output contains the number M representing the number of possibilities to poise the balance.

            Sample Input

            2 4	
            -2 3 
            3 4 5 8
            

            Sample Output

            2

            Source

            Romania OI 2002
            郁悶了,dp不會了 昨天吃晚飯回來就做,到走才知道題目意思看錯了,《岳陽樓記》也不會了
            。。。。。郁悶,代碼很爛,不發了
            posted on 2009-02-20 09:25 KNIGHT 閱讀(270) 評論(0)  編輯 收藏 引用
            <2009年2月>
            25262728293031
            1234567
            891011121314
            15161718192021
            22232425262728
            1234567

            常用鏈接

            留言簿(8)

            隨筆檔案

            文章檔案

            Friends

            OJ

            搜索

            •  

            最新評論

            閱讀排行榜

            評論排行榜

            99精品久久精品| 久久精品国产亚洲Aⅴ蜜臀色欲| 日韩欧美亚洲综合久久影院Ds | 老男人久久青草av高清| 精品国产99久久久久久麻豆| 久久亚洲春色中文字幕久久久 | 久久综合狠狠综合久久综合88| 国产成年无码久久久久毛片| 久久精品不卡| 久久av无码专区亚洲av桃花岛| 亚洲综合久久综合激情久久 | 国产精品久久婷婷六月丁香| 久久婷婷国产综合精品| 亚洲欧美成人久久综合中文网 | 精品久久一区二区三区| 伊人久久精品影院| 国产激情久久久久影院| 精品永久久福利一区二区| 亚洲国产成人久久综合野外| 999久久久免费精品国产| 久久国内免费视频| 久久精品国产一区二区电影| 青青青青久久精品国产h| 色婷婷综合久久久久中文| 少妇人妻综合久久中文字幕| 久久久国产一区二区三区| 狠狠色丁香久久婷婷综| 精品久久久久久成人AV| 亚洲级αV无码毛片久久精品| 亚洲精品高清一二区久久| 久久久久国产一区二区三区| 18岁日韩内射颜射午夜久久成人 | 国产成人99久久亚洲综合精品 | 精品久久久久久国产三级| 久久青草国产手机看片福利盒子| 婷婷综合久久中文字幕蜜桃三电影| 久久亚洲精品国产亚洲老地址| 蜜臀久久99精品久久久久久| 热久久国产欧美一区二区精品| 欧美久久综合九色综合| 中文成人无码精品久久久不卡|