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UISearchBar控�g�Q��{载）

Wed, 04 Mar 2015 11:23:00 GMT

摘要: UISearchBar控�g��是要�ؓ你完成搜索功能的一个专用控件。它集成了很多你意想不到的功能和特点�Q�首先，�q�是来普及一下UISearchBar控�gAPI相关的属性和�Ҏ��吧！UISearchBar属性相关_searchBar = [[UISearchBar alloc] initWithFrame:CGRectZero];// 初始化，不解�?nbsp;&nb... 阅读全文

王�v�?/a> 2015-03-04 19:23 发表评论

(转蝲)推荐�Q�国外程序员整理�?C++ 资源大全

Fri, 14 Nov 2014 00:58:00 GMT

摘要: 标准库C++标准库，包括了STL容器�Q�算法和函数�{�。C++ Standard Library�Q�是一�p�d��c�d��函数的集合，使用核心语言�~�写�Q�也是C++ISO自��n标准的一部分。Standard Template Library�Q�标准模板库C POSIX library �Q?POSIX�pȝ��的C标准库规范ISO C++ Standards Committee �Q�C++标准委员�?nbsp... 阅读全文

王�v�?/a> 2014-11-14 08:58 发表评论

MFC wcslen获取中文长度

Fri, 10 Oct 2014 03:53:00 GMT

不知道大家有没有我这�U�体�?大家先看看下面这�D�代�?

int fp=_wopen(L"Hello.dat",O_BINARY | O_CREAT | O_TRUNC | O_RDWR);
if(fp==-1) return;
write(fp,L"123中国�?,wcslen(L"123中国�?));
close(fp);

上面�q�段代码不知道大家看��Z��么BUG来了.如果大家看不出毛病也不��为�?因�ؓ�q�是我们的习惯导致了我们的错误��?

先让我来分析一下write�?下面是write的原�?
int write( int handle, const void *buffer, unsigned int count );
参数:
handle 已打开或已创徏的文件句�?/span>
buffer 待写入的数据
count 待写入的数据大小
现在分析��Z��么上面的那代码有bug,其实主要问题��在一个buffer,和count.
如果我们写入一个Ansi字符�?上面的代码改成相应的形式��实没有�?
但如果是写入一个宽字符�?那么上面的代码就不严�?原因��在于count.

我们首先看一下strlen�?/span>wcslen,如果使用strlen,一般情况下,我们直接作�ؓ字符串的长度,
而��?/span>wcslen,你会发现,得出的不是字�W�串的长度而是字符的个�?

�q�就是问题的所�?一般情况下.char的长度是1,�q�是用sizeof(char)�q�算出来的结�?
len=strlen(str)*sizeof(char);而我们一般情况下,都只用strlen(str)来等�?�q�就是��^时的习惯.
正是�׃��q�个习惯所引来的问�?�q�个习惯�q�不适用于宽字符�?因�ؓwcslen(str)*sizeof(wchar_t)�q�不�{�于wcslen(strl).�q�就是习惯所引�v的错�?

说到�q�里我想大家都明白了.我在�q�里把这�U�习惯称之�ؓ不良习惯.所以大家以后在计算字符串长度的时�?千万不能��而简�?一定要len=strlen(str)*sizeof(char),len=wcslen(str)*sizeof(wchar_t).
不要再犯�q�种习惯性的低��错误.

本文转自�Q?a >http://blog.csdn.net/aylixuan/article/details/6130820

王�v�?/a> 2014-10-10 11:53 发表评论

Gloox文�g传输��记

Tue, 02 Sep 2014 09:18:00 GMT

使用版本�Q?.1.10

今天弄了一下Gloox中自带的收发文�g例子�Q�收发文件的例子都是好��的，只不�q�，在调试过�E�中需要注意一些问题，下面��我遇到的问题做个记录（例子中以In-Band Bytestreams方式收发�Q?/span>�?/span>

1、发送文件过�E�中遇到404错误

<iq type='error' id='uid-8509a748-00000005' to='wanghaiguang@wanghaiguang-wk/glooxsendfile'from='www@192.168.60.67/Spark 2.6.3'><sixmlns='http://jabber.org/protocol/si' id='uid-8509a748-00000006' profile='http://jabber.org/protocol/si/profile/file-transfer'>xmlns='http://jabber.org/protocol/si/profile/file-transfer' name='d:\offline.bmp' size='6998'/>xmlns='http://jabber.org/protocol/feature-neg'>xmlns='jabber:x:data' type='form'>type='list-single'var='stream-method'>label='ibb'>http://jabber.org/protocol/ibblabel='oob'>jabber:iq:ooblabel='s5b'>http://jabber.org/protocol/bytestreamscode='404' type='cancel'>xmlns='urn:ietf:params:xml:ns:xmpp-stanzas'/>

可以��ip地址换成服务器名�U�试�?/span>

JID j( "www@192.168.60.67/gloox" );——> JID j( "www@wanghaiguang-wk/gloox" );

2�?/strong>发送文件过�E�中遇到503错误
<iq type='error' id='uid-8663a748-00000005' from='www@wanghaiguang-wk/glooxsend'to='wanghaiguang@wanghaiguang-wk/glooxsendfile'>xmlns='http://jabber.org/protocol/si' id='uid-8663a748-00000006' profile='http://jabber.org/protocol/si/profile/file-transfer'>xmlns='http://jabber.org/protocol/si/profile/file-transfer' name='d:\offline.bmp' size='6998'/>xmlns='http://jabber.org/protocol/feature-neg'>xmlns='jabber:x:data' type='form'>type='list-single' var='stream-method'>label='ibb'>http://jabber.org/protocol/ibblabel='oob'>jabber:iq:ooblabel='s5b'>http://jabber.org/protocol/bytestreamscode='503' type='cancel'>xmlns='urn:ietf:params:xml:ns:xmpp-stanzas'/>

�q�个问题可能是由于你接收端的资源名称与发送端不匹�?/span>
//接收端登录的jid
JID jid( "www@192.168.60.67/glooxsendfile" );
j = new Client( jid, "111" );

//发送端的jid名称�Q�发送给�Ҏ��的jid名称�Q?/span>
JID j( "www@wanghaiguang-wk/gloox" );
if( j.resource().empty() )
{
printf( "error: need full jid\n" );
return 1;
}

王�v�?/a> 2014-09-02 17:18 发表评论

GLOOX 1.0.10注册问题

Thu, 28 Aug 2014 09:59:00 GMT

引文�Q?/strong>
调试GLOOX 1.0.10的注册功能颇费了一些功夫。��M��逻辑如GLOOX自带的例子一��h��毫无疑问的，但是照搬例子又是不能完成注册的，�q�回错误码�ؓ4------RegistrationBadRequest�?span style="font-size: 14pt;">�W�者一开�?/span>在网上狂搜解��x��案，资料��之又少�Q�有��重写Client::handleNormalNode函数�Q�目的是��止SASL认证�Q�的�Q�有直接�l�承Client重写Client::handleNormalNode函数的，但都没说到点子上。经�q�一�D�|��间的研究�Q�在GLOOX�?/span>maillist上得到启发，��利完成注册。现��解��x��案记录下来：

环境
客户端：GLOOX1.0.1.0 VS2008
服务器：OPENFIRE 默认安装

对于GLOOX自带的注册例子不能正常注册的问题有�h在邮件列表里提出来。一个哥们这样回�{�：
Ok, I've found what the problem was
In openFire server parameters, Anonymous Login => Disabled !!!

意思是�?/span>��用openFire服务器里的选项”注册和登�?#8220;�?#8221;匿名��d��“��?/strong>�?/span>
�W�者按此说明禁用该选项�Q�果然注册成功�?/span>
�q�说明开始的注册��p�|是和匿名��d��有关�pȝ��。我们来看一下引用registration_expmple例子��d��p�|时的XML��：
S->C�Q�服务器�q�回�l�客��L��支持的认证机�Ӟ��
<stream:features xmlns:stream='http://etherx.jabber.org/streams'>xmlns='urn:ietf:params:xml:ns:xmpp-sasl'>DIGEST-MD5PLAINANONYMOUSCRAM-MD5xmlns='http://jabber.org/features/compress'>zlibxmlns='http://jabber.org/features/iq-auth'/>xmlns='http://jabber.org/features/iq-register'/>

从上面XML��中我们可以看到�Q�默认openFire支持四种认证机制�Q�分别是�Q�DIGEST-MD5、PLAIN、ANONYMOUS、CRAM-MD5。然后我们看GLOOX客户端的响应��：
C->S�Q�客��L��q�回选择的认证方式：
<auth xmlns='urn:ietf:params:xml:ns:xmpp-sasl' mechanism='ANONYMOUS'/>

可以看出�Q�客��L��”无�?#8220;的选择�?#8221;匿名“--'ANONYMOUS'方式
接下来的��程��是客户�?#8221;无�?#8220;的选择了以匿名的方式登录了服务器，然后再发送注册请求，��h��如下�Q?/p>
<iq id='uid:4e69eccd:00006784' type='set' from='447e0585@zxl/447e0585' xmlns='jabber:client'><query xmlns='jabber:iq:register'><username>bbaxiaousername><password>123456password><name>test2name><email>163@gmail.comemail>query>iq>

我们看到�Q�IQ节里包含“form”属性，卛_��L��匿名�w�䆾标识�?/span>
注意�Q�一个客��L��已经以一个��n份（由服务器临时分配的一个JID�Q�登录，建立了会话，在服务器上我们会看到�q�个会话�Q��ƈ且服务器发送心跳一直维护这个会话。这�U�情况下�Q�这个客��L��再发送注册请求（另一个��n份）建立与服务器的连接是不被允许的。具体请参考XEP-0077�Q�In-Band Registration�Q�：我们��x��q�两�D�：
If the entity cancels its registration with its "home" server (i.e., the server at which it has maintained its XMPP account), then the entity SHOULD NOT include a 'from' or 'to' address in the remove request the server SHOULD then return a  stream error and terminate all active sessions for the entity. The server SHOULD perform the remove based on the bare JID  associated with the current session or connection over which it received the remove request. If the server is an instant messaging and presence server that conforms to XMPP IM [8], the server SHOULD also cancel all existing presence subscriptions related to that entity (as stored in the entity's roster).

If the entity cancels its registration with a service other than its home server, its home server MUST stamp a 'from' address on the remove request, which in accordance with XMPP Core will be the entity's full JID . The service MUST perform the remove based on the bare JID  portion of the 'from' address.

If the entity cancels its registration with its "home" server (i.e., the server at which it has maintained its XMPP account), then the entity SHOULD NOT include a 'from' or 'to' address in the remove request the server SHOULD then return a  stream error and terminate all active sessions for the entity. The server SHOULD perform the remove based on the bare JID  associated with the current session or connection over which it received the remove request. If the server is an instant messaging and presence server that conforms to XMPP IM [8], the server SHOULD also cancel all existing presence subscriptions related to that entity (as stored in the entity's roster).

If the entity cancels its registration with a service other than its home server, its home server MUST stamp a 'from' address on the remove request, which in accordance with XMPP Core will be the entity's full JID . The service MUST perform the remove based on the bare JID  portion of the 'from' address.

意思是说注册请求不能包�?#8220;from”属性�?/span>
正常的注册流如下�Q?/span>
<iq id='uid:4e69eccd:00003d6c' type='set' xmlns='jabber:client'>xmlns='jabber:iq:register'>bbaxiao123456test2163@gmail.com

---------------------------
�l�g��所�q�ͼ�解决�Ҏ��如下�Q?/span>
一、关闭openFire的匿名登录功能。^_^……
二、禁止GLOOX匿名认证功能�?/span>
file:client.cpp

fun: int Client::getSaslMechs( Tag* tag )

line:423

//��?23行注释掉卛_��?nbsp;
422�Q�if( tag->hasChildWithCData( mech, "ANONYMOUS" ) )
423 //mechs |= SaslMechAnonymous;

重新�~�译生成DLL卛_��?/span>
三、手动设�|�GLOOX客户端SASL认证机制
在调用j->connect()之前讄��SASL认证机制�Q�比如设�|��ؓ“DIGEST-MD5”

j->setSASLMechanisms(SaslMechDigestMd5);

�q�种方式的缺�Ҏ��需要先��定服务器支持的认证机制�?/span>
四、根据XEP-0077所�q�ͼ�即��其名��d��Q�注册流只要不带“from”属性应该也可以。所以我们要处理发出的注册流�Q�去�?#8220;from”属性重新发送注册流卛_��?/span>

本文转自�Q?/strong>http://blog.csdn.net/abcpanpeng/article/details/7370974

王�v�?/a> 2014-08-28 17:59 发表评论

Mon, 18 Aug 2014 01:45:00 GMT
NSString中如果包括中文字�W�，在�{换�ؓNSURL时得到的��gؓnil

解决办法�Q?/span>

NSString *urlString = [NSString stringWithFormat:@"http://api.openweathermap.org/data/2.5/weather?q=%@&units=imperial",cityName];
urlString = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [NSURL URLWithString:urlString];
NSLog(@"%@", url);

王�v�?/a> 2014-08-18 09:45 发表评论

Fri, 01 Aug 2014 05:31:00 GMT
�W�一�?
创徏2个NSNotificationCenter监听

[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(applicationWillResignActive:) name:UIApplicationWillResignActiveNotification object:nil]; //监听是否触发home键挂��L��? [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(applicationDidBecomeActive:) name:UIApplicationDidBecomeActiveNotification object:nil]; //监听是否重新�q�入�E�序�E�序.

�W�二�?
实现2个NSNotificationCenter所触发的事件方�?/span>

- (void)applicationWillResignActive:(NSNotification *)notification { printf("按理说是触发home按下\n"); } - (void)applicationDidBecomeActive:(NSNotification *)notification { printf("按理说是重新�q�来后响应\n"); }

�? 在home键触发后,AppDelegate响应的方法�ؓ:

- (void)applicationDidEnterBackground:(UIApplication *)application { /* Use this method to release shared resources, save user data, invalidate timers,

and store enough application state information to restore your application to its current state in case it is terminated later. If your application supports background execution, this method is called instead of applicationWillTerminate: when the user quits. */ }

本文转自�Q?/span>http://blog.csdn.net/sqc3375177/article/details/9466687

其他相关信息�Q?/div>

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions

{

    // Override point for customization after application launch.

    NSLog(@"\n ===> �E�序开�?nbsp;!");



    return YES;

}



- (void)applicationWillResignActive:(UIApplication *)application

{



    NSLog(@"\n ===> �E�序暂行 !");

}



- (void)applicationDidEnterBackground:(UIApplication *)application

{



     NSLog(@"\n ===> �E�序�q�入后台 !");

}



- (void)applicationWillEnterForeground:(UIApplication *)application

{



     NSLog(@"\n ===> �E�序�q�入前台 !");

}



- (void)applicationDidBecomeActive:(UIApplication *)application

{

    NSLog(@"\n ===> �E�序重新�Ȁ�z?nbsp;!");



}



- (void)applicationWillTerminate:(UIApplication *)application

{

    NSLog(@"\n ===> �E�序意外暂行 !");



    UIDevice *device = [UIDevice currentDevice];



}

首次�q�行�Q?/p>
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions

- (void)applicationDidBecomeActive:(UIApplication *)application

首次关闭�Q�home�Q�：

- (void)applicationWillResignActive:(UIApplication *)application

- (void)applicationDidEnterBackground:(UIApplication *)application

再次�q�行�Q?/span>

- (void)applicationWillEnterForeground:(UIApplication *)application

- (void)applicationDidBecomeActive:(UIApplication *)application

再次关闭�Q?/span>

- (void)applicationWillResignActive:(UIApplication *)application

- (void)applicationDidEnterBackground:(UIApplication *)application

本文转自�Q�http://friendlysong.blog.163.com/blog/static/3225243920128144251666/

王�v�?/a> 2014-08-01 13:31 发表评论

Tue, 29 Jul 2014 05:35:00 GMT
     摘要: UIGestureRecognizer 是一个具体手势的基类�Q�提供了较�ؓ��单的手势实现方式 The concrete subclasses of UIGestureRecognizer are the following:UITapGestureRecognizerUIPinchGestureRecognizerUIRotationGestureRecog...  阅读全文

王�v�?/a> 2014-07-29 13:35 发表评论

Tue, 15 Jul 2014 05:50:00 GMT
�?/span>“Header Search Paths” 中添�?/span>“/usr/include/libxml2″
�?/span>“Other Linker Flags”��d��“-lxml2″
�q�行后出现错误找不到

解决办法�Q?/span>�?/span>“Header Search Paths” 中添�?/span> ${SDKROOT}/usr/include/libxml2

王�v�?/a> 2014-07-15 13:50 发表评论

国产精品久久久久影院嫩草 ,国产精品伦理久久久久久,亚洲精品tv久久久久

UISearchBar控�g�Q��{载）

(转蝲)推荐�Q�国外程序员整理�?C++ 资源大全

MFC wcslen获取中文长度

Gloox文�g传输���记

GLOOX 1.0.10注册问题

Gloox文�g传输��记