The thread to which the message is posted must have created a message queue, or else the call to PostThreadMessage fails. Use one of the following methods to handle this situation.

• Call PostThreadMessage. If it fails, call the Sleep function and call PostThreadMessage again. Repeat until PostThreadMessage succeeds.
• Create an event object, then create the thread. Use the WaitForSingleObject function to wait for the event to be set to the signaled state before calling PostThreadMessage. In the thread to which the message will be posted, call PeekMessage as shown here to force the system to create the message queue.

  PeekMessage(&msg, NULL, WM_USER, WM_USER, PM_NOREMOVE)

  Set the event, to indicate that the thread is ready to receive posted messages.

        看來，我們只需要在線程初始化時(shí)調(diào)一句PeekMessage(&msg, NULL, WM_USER, WM_USER, PM_NOREMOVE)就可以了，然后在主線程中如此這般：

switch ( uMsg )
        {
        case WM_PAINT:
            {
                hdc = BeginPaint(hWnd, &ps);
                EndPaint(hWnd, &ps);
            }
            break;
        case WM_DESTROY:
            {
                m_pLogic->StopThread();
                WaitForSingleObject( m_pLogic->GetThreadHandle(), INFINITE );
                PostQuitMessage(0);
            }
            break;
        default:
            {
                if ( IsLogicMsg( uMsg ) )
                {
                    PostThreadMessage( m_pLogic->GetThreadID(), uMsg, wParam, lParam );
                }
                else
                {
                    return DefWindowProc( hWnd, uMsg, wParam, lParam );
                }
            }
            break;
        }

MSG msg;
        while ( m_bRunning )
        {
            if ( PeekMessage( &msg, NULL, 0, 0, PM_NOREMOVE ) )
            {
                if ( ! GetMessageW( &msg, NULL, 0, 0 ) )
                {
                    return (int) msg.wParam;
                }

                MessageProc( msg.message, msg.wParam, msg.lParam );
            }

            LogicTick();
        }