先看一段代碼:
它輸出結(jié)果如下:
B7D19FB0, B7D19FB4, B7D19FB8,
B7D19FB0, B7D19FB4,
B7D19FB0, B7D19FB4, B7D19FB8,
B7D1CFA0, B7D1CFA4, B7D1CFA8, B7D1CFAC,
可以看到前3行地址相同,后面一行地址不同。為什么?
D語(yǔ)言的數(shù)組分配是內(nèi)存緊湊的,當(dāng)減小數(shù)組長(zhǎng)度減小時(shí),只需要修改切片大小而不需要重新分配。當(dāng)長(zhǎng)度變大時(shí),也會(huì)檢查原來(lái)的緩沖區(qū)是否夠大,以確定是否需要重新分配空間。注意第2次操作時(shí)把長(zhǎng)度恢復(fù)為原來(lái)大小時(shí),并非真的恢復(fù)了原來(lái)的狀態(tài),后面長(zhǎng)出來(lái)的元素會(huì)被初始化為默認(rèn)值。
再來(lái)看一個(gè):
在執(zhí)行int[] d = c;以后,d的確是和c共享了存儲(chǔ)區(qū)。不過(guò)在改變d的長(zhǎng)度以后,它就和c分道揚(yáng)鑣了。所以int[] d = c不能理解為d是一個(gè)指向c的引用,它實(shí)際上創(chuàng)建了一個(gè)新的數(shù)組對(duì)象,但并不拷貝數(shù)組元素,它和int[] d = c[0 .. length]是等價(jià)的,都是數(shù)組切片操作。
這個(gè)問(wèn)題讓我困惑不已。比如你用char[]表示一個(gè)單詞,用char[][]表示一行,char[][][]表示多行。如何引用這個(gè)單詞?你當(dāng)然可以每次使用lines[i][j],但如果處理步驟很多,這會(huì)不會(huì)看起來(lái)很頭大?
看上去應(yīng)該這樣使用:
可惜根據(jù)前面的結(jié)論,這將無(wú)法影響到lines。如果找不到一個(gè)引用類型指向數(shù)組,有時(shí)候使用起來(lái)還真是很麻煩??雌饋?lái)把Line/Word包裝成類是個(gè)勉強(qiáng)湊合的主意。。。
void?main(){
????int[]?c?=?[1,2,3];
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????c.length?=?2;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????c.length?=?3;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????c.length?=?4;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
}
????int[]?c?=?[1,2,3];
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????c.length?=?2;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????c.length?=?3;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????c.length?=?4;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
}
它輸出結(jié)果如下:
B7D19FB0, B7D19FB4, B7D19FB8,
B7D19FB0, B7D19FB4,
B7D19FB0, B7D19FB4, B7D19FB8,
B7D1CFA0, B7D1CFA4, B7D1CFA8, B7D1CFAC,
可以看到前3行地址相同,后面一行地址不同。為什么?
D語(yǔ)言的數(shù)組分配是內(nèi)存緊湊的,當(dāng)減小數(shù)組長(zhǎng)度減小時(shí),只需要修改切片大小而不需要重新分配。當(dāng)長(zhǎng)度變大時(shí),也會(huì)檢查原來(lái)的緩沖區(qū)是否夠大,以確定是否需要重新分配空間。注意第2次操作時(shí)把長(zhǎng)度恢復(fù)為原來(lái)大小時(shí),并非真的恢復(fù)了原來(lái)的狀態(tài),后面長(zhǎng)出來(lái)的元素會(huì)被初始化為默認(rèn)值。
再來(lái)看一個(gè):
void?main(){
????int[]?c?=?[1,2,3];
????int[]?d?=?c;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????foreach(inout?int?i;?d){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????d.length?=?2;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????foreach(inout?int?i;?d){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????d.length?=?4;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????foreach(inout?int?i;?d){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
}
????int[]?c?=?[1,2,3];
????int[]?d?=?c;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????foreach(inout?int?i;?d){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????d.length?=?2;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????foreach(inout?int?i;?d){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????d.length?=?4;
????foreach(inout?int?i;?c){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
????foreach(inout?int?i;?d){
????????writef(&i);
????????writef(",?");
????}
????writefln("");
}
在執(zhí)行int[] d = c;以后,d的確是和c共享了存儲(chǔ)區(qū)。不過(guò)在改變d的長(zhǎng)度以后,它就和c分道揚(yáng)鑣了。所以int[] d = c不能理解為d是一個(gè)指向c的引用,它實(shí)際上創(chuàng)建了一個(gè)新的數(shù)組對(duì)象,但并不拷貝數(shù)組元素,它和int[] d = c[0 .. length]是等價(jià)的,都是數(shù)組切片操作。
這個(gè)問(wèn)題讓我困惑不已。比如你用char[]表示一個(gè)單詞,用char[][]表示一行,char[][][]表示多行。如何引用這個(gè)單詞?你當(dāng)然可以每次使用lines[i][j],但如果處理步驟很多,這會(huì)不會(huì)看起來(lái)很頭大?
看上去應(yīng)該這樣使用:
char[][][]?lines;
char[][]?line?=?lines[0];
line.length?=?line.length?+?1;
line[length?-?1]?=?",";
char[][]?line?=?lines[0];
line.length?=?line.length?+?1;
line[length?-?1]?=?",";
可惜根據(jù)前面的結(jié)論,這將無(wú)法影響到lines。如果找不到一個(gè)引用類型指向數(shù)組,有時(shí)候使用起來(lái)還真是很麻煩??雌饋?lái)把Line/Word包裝成類是個(gè)勉強(qiáng)湊合的主意。。。