锘??xml version="1.0" encoding="utf-8" standalone="yes"?>国产精品久久国产愉拍
,1024日韩,99亚洲伊人久久精品影院红桃http://www.shnenglu.com/Going/category/10325.htmlzh-cnSun, 26 Apr 2009 08:31:00 GMTSun, 26 Apr 2009 08:31:00 GMT60- hdu 1203 I NEED A OFFER!http://www.shnenglu.com/Going/archive/2009/04/26/81098.htmlGoingGoingSun, 26 Apr 2009 01:27:00 GMThttp://www.shnenglu.com/Going/archive/2009/04/26/81098.htmlhttp://www.shnenglu.com/Going/comments/81098.htmlhttp://www.shnenglu.com/Going/archive/2009/04/26/81098.html#Feedback0http://www.shnenglu.com/Going/comments/commentRss/81098.htmlhttp://www.shnenglu.com/Going/services/trackbacks/81098.html
#include<iostream>
#include<algorithm>
#include<cstdio>
using namespace std;

typedef struct node


{
int price;
double bb;
}Node;

Node a[1005];

bool cmp(Node a,Node b)


{
if(a.bb != b.bb)
return a.bb < b.bb;
else
return a.price < b.price;
}

int main()


{
int n,m;
while(cin>>n>>m)

{
if(n == 0 && m == 0)
break;
int i;
for(i = 1;i <= m;i++)

{
cin>>a[i].price>>a[i].bb;
a[i].bb = 1.0-a[i].bb;
}
sort(a+1,a+m+1,cmp);
int mon = 0;
double sum = 1.0;
for(i = 1;i <= m;i++)

{
if(mon + a[i].price <= n)

{
mon = mon + a[i].price;
sum = sum * a[i].bb;
}
}
sum = (1-sum)*100;
printf("%.1lf%%\n",sum);
}
return 0;
}

]]> - hutc 1040 Knapsack Problem 璐績http://www.shnenglu.com/Going/archive/2009/04/22/80717.htmlGoingGoingWed, 22 Apr 2009 05:59:00 GMThttp://www.shnenglu.com/Going/archive/2009/04/22/80717.htmlhttp://www.shnenglu.com/Going/comments/80717.htmlhttp://www.shnenglu.com/Going/archive/2009/04/22/80717.html#Feedback0http://www.shnenglu.com/Going/comments/commentRss/80717.htmlhttp://www.shnenglu.com/Going/services/trackbacks/80717.html
#include<iostream>
#include<algorithm>
using namespace std;

typedef struct node


{
double w;
double v;
}Node;

Node b[20005];

bool cmp(Node a,Node b)


{
return (a.v/a.w) > (b.v/b.w);
}

int main()


{
int n;
double c;
while(cin>>n>>c)

{
int i;
for(i = 0;i < n;i++)
cin>>b[i].w;
for(i = 0;i < n;i++)
cin>>b[i].v;
sort(b,b+n,cmp);
double sum = 0.0;
for(i = 0;i < n;i++)

{
if(b[i].w <= c)

{
sum += b[i].v;
c = c-b[i].w;
}
else

{
break;
}
}
if(i <= n)

{
sum = sum + c * b[i].v/b[i].w;
}
printf("%.1lf\n",sum);
}
return 0;
}

]]>
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